Answer:
Explanation:
Orbital radius of satellite A , Ra = 6370 + 6370 = 12740 km
Orbital radius of satellite B , Rb = 6370 + 19110 = 25480 km
Orbital potential energy of a satellite = - GMm / r where G is gravitational constant , M is mass of the earth and m is mass of the satellite
Orbital potential energy of a satellite A = - GMm / Ra
Orbital potential energy of a satellite B = - GMm / Rb
PE of satellite B /PE of satellite A
= Ra / Rb
= 12740 / 25480
= 1 / 2
b ) Kinetic energy of a satellite is half the potential energy with positive value , so ratio of their kinetic energy will also be same
KE of satellite B /KE of satellite A
= 1 / 2
c ) Total energy will be as follows
Total energy = - PE + KE
- P E + PE/2
= - PE /2
Total energy of satellite B / Total energy of A
= 1 / 2
Satellite B will have greater total energy because its negative value is less.
Answer:
I guess that the atoms are:
Protons: 6 8 5 2 12 12
Neutrons: 8 8 5 3 13 14
Now, two atoms are isotopes if they share the same number of protons (so both atoms are the same element) but they have a different number of neutrons.
From the given options, the only two that have the same number of protons but a different number of neutrons are:
Protons 12, neutrons 13
and
Protons 12, neutrons 14.
These two are isiotopes.
Kinetic energy = (1/2) (mass) (speed)²
= (1/2) (1.4 kg) (22.5 m/s)²
= (0.7 kg) (506.25 m²/s² )
= 354.375 kg-m²/s² = 354.375 joules .
This is just the kinetic energy associated with a 1.4-kg glob of
mass sailing through space at 22.5 m/s. In the case of a frisbee,
it's also spinning, and there's some additional kinetic energy stored
in the spin.
Answer:
Assuming there are 28 days in each month,
750W = 0.75kW
Cost of electric bill = 0.75 × 8 × 28 × $0.23
= $38.64
The momentum increases by a factor of 2
Explanation:
We can solve this problem by rewriting the momentum of the rocket in terms of the kinetic energy and the mass.
The kinetic energy of the rocket is:
(1)
where
m is the mass
v is the velocity
The momentum of the rocket is
(2)
From eq.(1) we get
![v=\sqrt{\frac{2K}{m}}](https://tex.z-dn.net/?f=v%3D%5Csqrt%7B%5Cfrac%7B2K%7D%7Bm%7D%7D)
and substituting into (2),
![p=\sqrt{2mK}](https://tex.z-dn.net/?f=p%3D%5Csqrt%7B2mK%7D)
Now in this problem we have:
- The kinetic energy of the rocket is increased by a factor 8:
![K' = 8K](https://tex.z-dn.net/?f=K%27%20%3D%208K)
- The mass is reduced by half:
![m'=\frac{m}{2}](https://tex.z-dn.net/?f=m%27%3D%5Cfrac%7Bm%7D%7B2%7D)
Substituting, we find the new momentum:
![p'=\sqrt{2(\frac{m}{2}(8K)}=\sqrt{4(2mK)}=2\sqrt{2mK}=2p](https://tex.z-dn.net/?f=p%27%3D%5Csqrt%7B2%28%5Cfrac%7Bm%7D%7B2%7D%288K%29%7D%3D%5Csqrt%7B4%282mK%29%7D%3D2%5Csqrt%7B2mK%7D%3D2p)
So, the momentum increases by a factor of 2.
Learn more about momentum and kinetic energy:
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