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3 years ago

About light and energy

1 answer:

7 0

E = MC^2. Albert Einstein's proven formula. When mass travels at the square of speed of light, the mass gets converted into energy

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The human nerve cells have a net negative charge and the material in the interior of the cell is a good conductor. if the cell h

mash [69]

The magnitude and direction (inward or outward) of the net flux through the cell boundary is - 0.887 wb.m².

Flux describes any effect that appears to pass or travel through a surface or substance.

The magnitude and direction (inward or outward) of the net flux through the cell boundary is calculated as follows;

Ф = Q/ε

where;

Q is net charge
ε is permittivity of free space

Φ = (-7.85 x 10⁻¹²)/(8.85 x 10⁻¹²)

Φ = - 0.887 wb.m²

Learn more about flux here: brainly.com/question/10736183

#SPJ1

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2 years ago

The planet Mars has a mass of 6.1 × 1023 kg and radius of 3.4 × 106 m. What is the acceleration of an object in free fall near t

Oksanka [162]

The acceleration due to gravity of Mars is $3.5\ m / s^{2}$

<u>Explanation:</u>

As per universal law of gravity, the gravitational force is directly proportional to the product of masses and inversely proportional to the square of the distance between them. But in the present case, the gravity need to be determined between Mars and the object on Mars. Since the mass of Mars is greater than the mass of any object. Thus,

$\text {Gravitational force of planet}=\frac{G M m}{R^{2}}$

Here, G is the gravitational constant, R is the radius of Mars and M, m is the mass of Mars and the object respectively..

Also, according to Newton’s second law of motion, the acceleration of any object will be equal to the ratio of force exerted on it to the mass of the object.

So in order to determine the acceleration due to gravity of Mars, divide the gravitational force of Mars by mass of object on the surface of Mars.

$Acceleration\ due\ to\ gravity\ of\ mars =\frac{\text {Gravitational force of Mars}}{m \text { of object }}$

$Acceleration\ due\ to\ gravity\ of\ mars =\frac{G M m}{R^{2} \times m}=\frac{G M}{R^{2}}$

$\text { Acceleration due to gravity of mars }=\frac{6.67259 \times 10^{-11} \times 6.1 \times 10^{23}}{3.4 \times 3.4 \times 10^{12}}=\frac{40.703 \times 10^{12}}{11.56 \times 10^{12}}$

$\text { Acceleration }=3.5\ \mathrm{m} / \mathrm{s}^{2}$

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3 years ago

Rubric for Grading O Activity3. Answer me! Directions: Compare and contrast the scientific method in philosophy and in science.

emmasim [6.3K]

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3 years ago

Julie has decided to manage her weight and has asked her friends for advice. Which of the following statements shows how Julie's

Semenov [28]

The answer to this question is c
"lets exercise and eat healthy foods together"<span />

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3 years ago

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A load of mass 5kg is raised through a height of 2m. calculate the work done against (g=10mls)

Illusion [34]

The work done against gravity is 100 J

Explanation: