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Butoxors [25]
4 years ago
6

A ball tossed vertically upward rises, reaches its highest point, and then falls back to its starting point. During this time th

e acceleration of the ball is always
A) in the direction of motion.
B) opposite its velocity.
C) directed upward.
D) directed downward.
Physics
1 answer:
kozerog [31]4 years ago
3 0

Answer: D) directed downward.

Explanation:

We know that the constant acceleration of 9.87ms^{-2} of every-thing is always DIRECT DOWNWARDS because of the to the influence of the gravity of the Earth.

This motion is denoted as free fall motion , where the acceleration due to the gravity is constant 9.87ms^{-2}.

∴ A ball tossed vertically upward rises, reaches its highest point, and then falls back to its starting point. During this time the acceleration of the ball is always  directed downward.

Hence, the correct answer is D) directed downward..

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Suppose that a nascar race car is moving to the right with a constant velocity of +86 m/s. What is the average acceleration of t
Stels [109]

(a) As the car is moving with constant velocity, it means the rate change of velocity does not change, therefore the average acceleration of the car is zero.

Thus, there is no acceleration, when velocity is constant.

(b) Average acceleration,

a =\frac{ v-u}{\Delta t}

Here, v is final velocity and u is the initial velocity and \Delta t is the time interval.

As twelve seconds later, the car is halfway around the track and traveling in the opposite direction with the same speed, therefore

a =\frac{ -86 \ m/s-86 \ m/s }{12 \ s} = - 14 .3 \ m/s^2

Thus, the average acceleration of the car is 14 .3 \ m/s^2 in the direction to the left.

6 0
3 years ago
Connie teaches her children to call adults "sir" and "ma'am" and to say "please" and "thank you." These rituals are known as
Nat2105 [25]
Manners. they are known as manners.
5 0
3 years ago
It takes Harry 34 s to walk from x1 = -11 m to x2 = -54 m .
miss Akunina [59]
Missing question:
"<span>What is his velocity? Please answer using two sig figs in m/s."

Solution
The relationship between velocity (v), space (S) and time (t) is
</span>v= \frac{S}{t}
<span>The space covered by Harry is
</span>S=x_1 - x_2 = -11 m-(-54 m)=43 m
<span>and so the velocity is 
</span>v= \frac{43 m}{34 s} =1.26 m/s<span>
</span>
4 0
4 years ago
A bomb of mass 6kg initially at rest explodes into two fragments of masses 4kg and2kg respectively. If the greater mass moves wi
uysha [10]

Answer:

v = 10 [m/s].

Explanation:

The largest mass is that of 4 [kg], in this way the momentum can be calculated by means of the product of the mass by velocity.

P=m*v\\

where:

P = momentum [kg*m/s]

m = mass = 4 [kg]

v = velocity = 5 [m/s]

Now the momentum:

P=4*5\\P=20[kg*m/s]

This same momentum is equal for the other mass, in this way we can find the velocity.

P=m*v\\20=2*v\\v=10[m/s]

4 0
3 years ago
Can somebody help please !!!!
Nataly [62]

Vector A is of magnitude 12 m and it makes an angle of 37 degree with Y axis

So here we can say that

\frac{A_x}{A} = sin37

A_x = A sin37

A_x = 12 sin37

A_x = 7.22 m

Similarly we have

\frac{A_y}{A} = cos37

A_y = A cos37

A_y = 12 cos37

A_y = 9.58 m

So here we have

A_y = 9.58 m, A_x = 7.22 m

option A is correct

3 0
3 years ago
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