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Butoxors [25]
3 years ago
6

A ball tossed vertically upward rises, reaches its highest point, and then falls back to its starting point. During this time th

e acceleration of the ball is always
A) in the direction of motion.
B) opposite its velocity.
C) directed upward.
D) directed downward.
Physics
1 answer:
kozerog [31]3 years ago
3 0

Answer: D) directed downward.

Explanation:

We know that the constant acceleration of 9.87ms^{-2} of every-thing is always DIRECT DOWNWARDS because of the to the influence of the gravity of the Earth.

This motion is denoted as free fall motion , where the acceleration due to the gravity is constant 9.87ms^{-2}.

∴ A ball tossed vertically upward rises, reaches its highest point, and then falls back to its starting point. During this time the acceleration of the ball is always  directed downward.

Hence, the correct answer is D) directed downward..

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I got this information for a lab but I don't know how to do the hypothesis and the conclusion please can you guys help me with i
pochemuha

Answer:

A hypothesis is what you think will happen.

A conclusion is the results of an experiment summarized.

Hope this helps.

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3 years ago
The refractive index n of transparent acrylic plastic (full name Poly(methyl methacrylate)) depends on the color (wavelength) of
Novosadov [1.4K]

Answer:

The angle between the blue beam and the red beam in the acrylic block is  

 \theta _d  =0.19 ^o

Explanation:

From the question we are told that

     The  refractive index of the transparent acrylic plastic for blue light is  n_F  =  1.497

     The  wavelength of the blue light is F  =  486.1 nm  =  486.1 *10^{-9} \ m

    The  refractive index of the transparent acrylic plastic for red light is  n_C  =  1.488

       The  wavelength of the red light is C =  656.3 nm  = 656.3 *10^{-9} \  m

    The incidence angle is  i  =  45^o

Generally from Snell's law the angle of refraction of the blue light  in the acrylic block  is mathematically represented as

       r_F =  sin ^{-1}[\frac{sin(i) *  n_a }{n_F} ]

Where  n_a is the refractive index of air which have a value ofn_a =  1

So

     r_F =  sin ^{-1}[\frac{sin(45) *  1 }{ 1.497} ]

      r_F  =  28.18^o

Generally from Snell's law the angle of refraction of the red light in the acrylic block is mathematically represented as

       r_C =  sin ^{-1}[\frac{sin(i) *  n_a }{n_C} ]

Where  n_a is the refractive index of air which have a value ofn_a =  1

So

     r_C =  sin ^{-1}[\frac{sin(45) *  1 }{ 1.488} ]

      r_F  =  28.37^o

The angle between the blue beam and the red beam in the acrylic block

     \theta _d  =  r_C  - r_F

substituting values

       \theta _d  = 28.37 -  28.18

       \theta _d  =0.19 ^o

 

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