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3 years ago

8

(question is on the top) I wanna say it's 13, however I keep getting 18 as the answer, I've been stuck on this for awhile now. a

ny help?

2 answers:

xxTIMURxx [149]3 years ago

8 0

Answer:

313 is the answer because

kondor19780726 [428]3 years ago

5 0

Answer:

Step-by-step explanation:

eighteen divided by three hundred thirteen

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Rzqust [24]

Answer:

Step-by-step explanation:

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2 years ago

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I need help with this question please?!!!

scoundrel [369]

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3 years ago

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Given that for an arithmetic sequence, the first term is q and the second term is qz.

otez555 [7]

Answer:

$d = q(z-1)$

$S_n = \frac{nq}{2}(2 + (n-1)(z-1))$

$S_{10} = 5q(9z -7)$

Step-by-step explanation:

Given

$T_1 = q$

$T_2 = qz$

Solving (a1): The common difference (d)

d is calculated as

$d = T_2 - T_1$

This gives:

$d = qz - q$

Factorize:

$d = q(z-1)$

Solving (a2): Sum of n terms

This is calculated using:

$S_n = \frac{n}{2}(2*T_1 + (n-1)d)$

Substitute values for T1 and d

$S_n = \frac{n}{2}(2*q + (n-1)q(z-1))$

$S_n = \frac{n}{2}(2q + q(n-1)(z-1))$

Factorize:

$S_n = \frac{n}{2}(q(2 + (n-1)(z-1)))$

$S_n = \frac{nq}{2}(2 + (n-1)(z-1))$

Solving (b): Sum of first 10.

In this case, n = 10

So:

$S_n = \frac{nq}{2}(2 + (n-1)(z-1))$

becomes

$S_{10} = \frac{10 * q}{2}(2 + (10-1)(z-1))$

$S_{10} = 5 * q(2 + 9(z-1))$

$S_{10} = 5q(2 + 9(z-1))$

$S_{10} = 5q(2 + 9z-9)$

$S_{10} = 5q(2 -9+ 9z)$

$S_{10} = 5q(-7+ 9z)$

$S_{10} = 5q(9z -7)$

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3 years ago

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Anna35 [415]

Answer:

a(bc)

Step-by-step explanation:

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3 years ago

Wins some money on the lottery. She uses 1/3 of her lottery win to buy a house

sp2606 [1]

Answer:11/96

Step-by-step explanation:

1-(1/3)=2/3=14/24

(2/3)-(1/8)=(14/24)-(3/24)=11/24

11/24 divided into 4 again is 11/96

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3 years ago