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- It is important to note that:
A nickel = $0.05
A dime = $0.10
We would be representing,
The number of nickels = n
The number of dimes = d
- Kendra has $3.15 in dimes and nickels. Writing this statement as an algebraic expression:
0.05n + 0.10d = 3.15...............Equation 1
- She has 4 times as many dimes as nickels. The algebraic expression for this statement :
4n = d ........................................ Equation 2
We would substitute 4n for d in Equation 1
0.05n + 0.10 x 4n = 3.15...............Equation 3
0.05n + 0.4n = 3.15
0.45n = 3.15
Divide both sides by 0.45
0.45n/0.45 = 3.15/0.45
n = 7
The number of nickels is 7
We solve for d, the number of dimes
4n = d
n = 7
4 x 7 = d
28 = d
The number of dimes is 28
Therefore, Kendra has 7 nickels and 28 dimes
To learn more, visit the link below:
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1 is b and 2 is j and 3 is d
Given that the 6.5% interest on the $5,500 loan is deferred during college, the amount Alex will pay upon graduation is <u>$81.67 </u>monthly.
<h3>How can the amount Alex will pay be found?</h3>
The number of years for the loan = 10-year
The loan amount = $5,500
The number of years for the interest = 6 years
The monthly payment formula is presented as follows;
Which gives;
- The amount Alex will pay upon graduation is <u>$81.67</u> each month
Learn more about monthly payment on loan formula;
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