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3 years ago

8

I need help on this.

1 answer:

jarptica [38.1K]3 years ago

5 0

Answer:

6:3, 24:12, 18:9 i think

Step-by-step explanation:

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What choice is a solution to the system of equations? y=2x-3 y-9=-x

Tema [17]

Answer:

$(4,5)\ or\ x=4,y=5$

Step-by-step explanation:

$We\ are\ given:\\y=2x-3\\y-9=-x\\Now,\ lets\ separate\ all\ the\ constant\ terms\ to\ the\ RHS\ and\ the\ variable\\ terms\ to\ the\ LHS.\\Hence,\\y-2x=-3\\y+x=9\\By\ subtracting\ the\ two\ equations:\\(y-2x)-(y+x)=(-3)-(9)\\Hence\ lets\ simplify\ this\ main\ equation: \\y-2x-(y+x)=-3-9\\y-2x-y-x=-12\\-3x=-12\\x=\frac{-12}{-3}=4\\\\Now,\ lets\ consider\ the\ second\ equation\ in\ the\ solution:\\y-9=-x\\Substituting\ x=4,\\y-9=-(4)\\y-9=-4\\y=-4+9\\y=5\\$

$Now,\\We\ get\ the\ solution\ to\ this\ system\ of\ equations:\\x=4,y=5\\By\ putting\ this\ as\ a\ co-ordinate\ pair (x,y):\\(4,5)$

8 0

3 years ago

Read 2 more answers

What is the slope of the line.

neonofarm [45]

Answer:

-1

Step-by-step explanation:

8 0

3 years ago

Plz no wrong answers <br> Find the next number in the pattern.<br><br> 9, 11, 15, 21, 29, 39, __

Maurinko [17]

Its 51, the numbers add 2 each time so 9 to 11 is 2 then you add 2 more for the next so 11 to 15 is 4 and so on

4 0

3 years ago

Determine if the set of polynomials {x^2 –2x+1, 2x² + 3x -4,-x2+x+5) is a linearly independent set in P2. Is it a basis for P? W

WITCHER [35]

Answer with Step-by-step explanation:

We are given that a set of polynomials ${x^2-2x+1,2x^2+3x-4,-x^2+x+5}$

We have to find that given set is a linearly independent set in $P_2$

and given set is a basis for $P_2$ or not.

Matrix of given set of polynomials

A= $\left[\begin{array}{ccc}1&-2&1\\2&3&-4\\-1&1&5\end{array}\right]$

Linearly Independent set :If any row or any column is not a linear combination of other rows or columns then the set is linearly independent set.

Any row or column is not a linear combination of other rows or columns.Therefore, given set is a linearly independent set .

We know that

$P_2=x^2$

Element of $P_2$ is of the form

$ax^2+bx+c$

Every element of $p_2$ is a linear combination of given set of polynomials.

Hence, given set is linearly independent in $p_2$ .

If any set is basis for any vector space then it satisfied the following two conditions

1.Given set is linearly independent.

2.Every element of given vector space spanned by the given set.

Given set of polynomials are linearly independent and spanned every element of $P_2$ .

Therefore, given set is as basis for $p_2$ because the set is linearly independent and spanned $P_2$ .

7 0

3 years ago

3x + 2y= 12<br><br> y = = x – 9<br> how do i solve this for substitution??

iren2701 [21]

In Point form: (6,-3)

In Equation form: x = 6, y = -3

Step-By-Step:

Solve for the first variable in one of the equations, then subsititute the result into the other equation

4 0

3 years ago