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larisa [96]
3 years ago
7

Math is hard don’t report me I have a question

Chemistry
1 answer:
GalinKa [24]3 years ago
8 0
Okay what’s the question?
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Which describes an element?
Deffense [45]
Answer: They cannot be broken down any further
6 0
2 years ago
Read 2 more answers
True or false 1. A scientific model is representation of a particular phenomena
cupoosta [38]

Answer:

True

Explanation:

The given statement is true.

A scientific model is defined as the mathematical and physical representation of a process or event. Scientists perform several observations or experiment and find a connection between them to prove a scientific finding.

A scientific model has the ability of explanatory power which helps to make things easier to understand using diagrams and consistency across contexts. Testing and prediction power in scientific models leads to strong predictions and able to convince people using an appropriate model.

Hence, the correct answer is "true".

4 0
3 years ago
A solution is made by dissolving 5.65 g of an unknown molecular compound in 110.0 g of benzene froze at 4.39 oc. what is the mol
Semenov [28]

Answer is: the molar mass of unknown molecular compound is 245.67 g/mol.

<span>m(compound) = 5.65 g.
m(benzene) = 110 g ÷ 1000 g/kg = 0.11 kg.
ΔT = 5.45°C - 4.39°C.</span>

ΔT = 1.06°C.

Kf(benzene) = 5.07°C/m.

<span>M(compound) = Kf · m(compound) / m(benzene) · ΔT.
M(compound)= 5.07°C/m · 5.65 g / (0.11 kg · 1.06°C).
M(compound) = 245.67 </span>g/mol.

6 0
3 years ago
Read 2 more answers
Draw the major product that is formed when 2-butyne is treated with hydrogen gas and lindlar catalyst.
Arada [10]

Major product is cis-2-butene.

You may find the structure in the attached picture.

Explanation:

In the presence of Lindlar catalyst the 2-butyne is hydrogenated to cis-2-butene (major product).

The chemical reaction is illustrated in the attached picture.

Learn more about:

hydrogenation

brainly.com/question/5793623

#learnwithBrainly

4 0
3 years ago
The half life of iodine-125 is 60 days. What fraction of 125I nuclides would be left after 360 days?
Agata [3.3K]

Answer:

THE FRACTION OF IODINE-125 REMAINING AFTER 360 DAYS IS 1/64.

Explanation:

half life of iodine- 125 = 60 days

Time elapsed for a decay = 360 days

using the formula:

                            Nt = No (1/2)^t/t1/2

The fraction left after a decay will be represented as:

Nt / No = (1/2) ^t/t1/2

Nt / No = (1/2) ^ 360 /60

Nt / No = (1/2) ^6

Nt / No = 1 / 64

The fraction of iodine-125 (Nt / No) remaining after 360 days is 1/ 64.

3 0
3 years ago
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