The correct answer is 1 to the 3rd power
Answer:
Explanation:
Your B-L Acid is a proton (Hydrogen, H+) donor, and your B-L base is a proton acceptor. This means that the base will take a hydrogen from your acid. NO2- is a B-L base, and you can tell it is a base by the negative charge it possesses. This means that it has a lone pair that wants to grab one of the hydrogens from NH4+, the B-L acid. In scientific words, the NO2- is a nucleophile and NH4+ is an electrophile. The result of NO2- grabbing that hydrogen from NH4+ is that NO2- becomes HNO2 (your conjugate acid) and and NH4+ becomes NH3 (you conjugate base). Basically, any time a B-L acid loses a proton, its equal product will be its conjugate base, and any time a B-L base gains a proton, its equal product will be its conjugate acid.
I hope this helped explain the concept behind Bronsted-Lowry acids and bases! Good luck with your class and please don't forget to give a positive rating! :-)
At the start of the Krebs cycle, acetyl CoA reacts with oxaloacetate molecule to form <span>citrate, a six-carbon molecule. he correct option among all the options that are given in the question is the third option or the penultimate option. I hope that this is the answer that has actually come to your great help.</span>
