What will be the efficiency of a machine which has an energy loss of 10%

Chemistry

1 answer:

Sauron [17]2 years ago

3 0

The efficiency of the machine which has an energy loss of 10% is 90%

<h3>What is efficiency? </h3>

This can be defined as the capacity to achieve a given task with little or no waste. Mathematically, it can be expressed as

Efficiency = (output / input) × 100

<h3>How to determine the efficiency </h3>

We shall assume the following:

Input = 100 J
Output = 100 – 10 = 90 J
Efficiency =?

Efficiency = (output / input) × 100

Efficiency = (90 / 100) × 100

Efficiency = 90%

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notsponge [240]

Kc= concentration of product divided by concentration of reactant
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3 years ago

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What orbitals are used to form the 10 sigma bonds in propane (ch3ch2ch3)? Label each atom with the appropriate hybridization. Dr

SVETLANKA909090 [29]

Mixing of pure orbitals having nearly equal energy to form equal number of completely new orbitals is said to be hybridization.

For the compound, $CH_3CH_2CH_3$ the electronic configuration of the atoms, carbon and hydrogen are:

Carbon (atomic number=6): In ground state= $1s^{2}2s^{2}2p^{2}$

In excited state: $1s^{2}2s^{1}2p^{3}$

Hydrogen (atomic number=1): $1s^{1}$

All the bonds in the compound is single bond( $\sigma$ -bond) that is they are formed by head on collision of the orbitals.

The structure of the compound is shown in the image.

The Carbon-Hydrogen bond is formed by overlapping of s-orbital of hydrogen to p-orbital of carbon.

In order to complete the octet the required number of electrons for carbon is 4 and for hydrogen is 1. So, the electron in $1s^{1}$ of hydrogen will overlap to the 2p^{3}-orbital of carbon.

Thus, the hybridization of Hydrogen is $s$ -hybridization and the hybridization of Carbon is $sp^{3}$ -hybridization.