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sergiy2304 [10]
3 years ago
6

Compared to a 1.0-gram sample of chlorine gas at standard pressure, a 1.0-gram sample of solid aluminum at standard pressure has

Chemistry
2 answers:
neonofarm [45]3 years ago
6 0

Answer: (2) a higher boiling point.


Justification:


1) These are teh melting point, boiling point, and density of chlorine and aluminum at STP (standard pressure and temperature).


                                            aluminum         chlorine

Melting point (°C)                  660.32             2470

Boiling point (°C)                   - 101.5           - 34.04

density (g / ml)                            2.7                 0.0032


From it, you can see that (1) and (3) are false, while (2) is true: aluminum has a higher melting point.


2) You can predict that from the fact that aluminun is a solid metal, so it has a high melting point compared with any gas at STP (which chlorine is).


3) About the volumes, since the density of aluminum is much less than that of chlorine, the same amount in grams (1.0 g) will occupy a smaller volume.



WITCHER [35]3 years ago
4 0
A greater volume due to mass of foil
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82.416 g of KNO ₃  is needed to produce 510.0 mL of a 1.6 M KNO ₃ solution.

Explanation:

Since molarity is the number of moles of solute that are dissolved in a given volume, calculated by dividing the moles of solute by the volume of the solution, the following rule of three can be applied: if in 1 L (1,000 mL) of KNO₃ there are 1.6 moles of the compound present, in 510 mL how many moles will there be?

moles=\frac{510 mL*1.6 moles}{1000 mL}

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Being the molar mass of the elements:

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So the molar mass of the compound KNO₃ is:

KNO₃= 39 g/mole + 14 g/mole + 3*16 g/mole= 101 g/mole

Now I can apply the following rule of three: if in 1 mole of KNO₃ there are 101 g, in 0.816 moles how much mass is there?

mass=\frac{0.816 moles*101 grams}{1 mole}

mass= 82.416 grams

<u><em>82.416 g of KNO ₃  is needed to produce 510.0 mL of a 1.6 M KNO ₃ solution.</em></u>

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