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nikklg [1K]
3 years ago
12

The _____ is a variation of circuit training that alternates upper body and lower body exercises throughout the circuit.

Physics
1 answer:
IrinaK [193]3 years ago
6 0

Answer:

peripheral heart action

Explanation:

The peripheral heart action is a variation of circuit training that alternates upper body and lower body exercises throughout the circuit.

Peripheral heart action practice is a method of interval bodybuilding training that was coined in the 1960s by former AAU Mr. America and Mr. Universe Bob Gajda. Most sources say that Gajda has always credited Arthur H. Steinhaus to create the concept behind PHA.

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Which one is true ?????
maria [59]

Answer:

b. horizontal distance/time graph

Explanation:

d is incorrect because object is moving at the same pace the entire time

7 0
3 years ago
A motion sensor acts as a transmitter when it sends out pulses and as a receiver when it listens for echoes. The delay ∆t betwee
Oksi-84 [34.3K]

Answer:

1.526 m

Explanation:

The motion sensor sends sound waves in air which travels at a speed of 343 m per second at 20 degree. If d be the distance of the reflecting object

total distance travelled = 2d

Time taken t = 8.9 x 10⁻³ s

velocity v  = 2d / t

343 = 2 d / (8.9 x 10⁻³)

d = 1.526 m

4 0
3 years ago
Hay represents two-dimensional motion
GREYUIT [131]

If a body is moving from left to right or right to left it is linear motion in x- direction. It is also called one dimensional motion.

If a body is moving up to down or down to up it is linear motion in y- direction. It is also called one dimensional motion.

But if a body is moving forward as well as downward it travels in X direction and in y direction at the same time. Such a motion is called two dimensional motion.

E.g motion of a ball.

Attachment shows path of two dimensional motion of a ball.

8 0
4 years ago
A transverse wave on a string is described by the wave function
fgiga [73]

The acceleration of the given wave is 2.5m/s^2

<h3>Wave property</h3>

The standard wave function is expressed according to the equation

y = Asin(2πft+2πx/λ)

where

λ is the wave length

Given the equation below

y = 0.120 sin((π/8)x + 4πt)

Compare both equation to have:

(π/8)x = 2πx/λ

8 = 2/λ

λ = 2/8

λ = 1/4

λ = 0.25m

For the frequency

Compare both equation to have:

4πt = 2πft

4 = 2f

4/2 = 2f/2

f = 2 Hz

Speed = fλ

speed = 2(0.25)

speed = 0.5m/s

Determine the acceleration

acceleration = change in velocity/time

acceleration = 0.5/ 0.200

acceleration = 2.5m/s^2

Hence the acceleration of the given wave is2.5m/s^2

Learn more on wave function here: brainly.com/question/25699025

#SPJ4

7 0
2 years ago
Calculate the total energy of 4.0 kg object moving horizontally at 20 m/s 50 meters above the surface.
Serhud [2]

Answer:

Correct answer:  E total = 2,800 J

Explanation:

Given:

m = 4 kg   the mass of the object

V = 20 m/s  the speed (velocity) of the object

H = 50 m the height of the object above the surface

E total = ? J

The total energy of an object is equal to the sum of potential and kinetic energy

E total = Ep + Ek

Ep = m g H   we take g = 10 m/s²

Ep = 4 · 10 · 50 = 2,000 J

Ek = m V² / 2

Ek = 4 · 20² / 2 = 2 · 400 = 800 J

E total = 2,000 + 800 = 2,800 J

E total = 2,800 J

God is with you!!!

4 0
4 years ago
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