<u>Answer</u>:
The radiant energy is converted into<u> electronic energy</u> before it is transformed into thermal energy.
<u>Explanation</u>:
Radiant energy occurs in the form of "Electromagnetic radiation" and it can pass through all types of matter travelling through the universe. There are numerous advantages of radiant energy. When the radiant energy is incident upon a substance the energy from the sun light excites the electrons in the atom. This sets the atoms in vibrational motion.
Thermal energy is the kinetic energy of moving particles. The thermal energy increases with increase in movement and number of moving particles. When the atoms make a transition from electronically excited state to vibrational state, the energy transfer increases the temperature of the substance. This is felt as thermal energy. Hence, the radiant energy is changed into "electronic energy" before it is converted into "thermal energy".
Explanation:
Red dwarf and brown dwarf masses are less than a typical white dwarf mass measuring around 1.2 solar masses. But it's only a few kilometers of the radius. This is precisely because there is no force to overcome the contraction due to gravity. There is a constant battle between the external force of fusion (who wants to expand the star) and inward pressure because of gravity (who wants to compact the star) of regular stars on the main sequence. There remains a balance between these two forces as long as the star remains on the celestial equator.
Red dwarfs are helped by the nuclear fusion force, but brown dwarfs were not large enough to cause the fusion of hydrogen, they are massive enough to generate sufficient energy in the core by fusing deuterium to sustain their volume. However as soon as the star runs out of hydrogen to burn it weakens the force of the external fusion and gravity starts to compact the center of the star. The contraction heats up the core into more massive stars and helium fusion begins, rendering the star once again stable. However this helium fusion does not occur in stars with masses below 1.44Mo. Tightness persists for such stars until the star's gasses degenerate.
Answer:
(a) Rm = 268.4 m
(b) f = 6
Explanation:
The horizontal range of a projectile is given by the following formula:
R = V₀² Sin 2θ/g
(a)
For moon:
R = Range on moon = Rm
V₀ = Launch Speed = 28 m/s
θ = Launch Angle = 17°
g = acceleration due to gravity on moon = (9.8 m/s²)/6 = 1.63 m/s²
Therefore,
Rm = (28 m/s)²Sin (2*17°)/(1.63 m/s²)
<u>Rm = 268.4 m</u>
(b)
For Earth:
R = Range on Earth = Re
V₀ = Launch Speed = 28 m/s
θ = Launch Angle = 17°
g = acceleration due to gravity on Earth = 9.8 m/s²
Therefore,
Re = (28 m/s)²Sin (2*17°)/(9.8 m/s²)
Re = 44.7 m
Therefore.
f = Rm/Re = 268.4 m/44.7 m
<u>f = 6</u>
