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TEA [102]
3 years ago
13

A motion sensor acts as a transmitter when it sends out pulses and as a receiver when it listens for echoes. The delay ∆t betwee

n sending the pulse and receiving the echo is equal to 8.9 ms. The air temperature is equal to 20º C. Part A What is the distance between the motion sensor and the object?
Physics
1 answer:
Oksi-84 [34.3K]3 years ago
4 0

Answer:

1.526 m

Explanation:

The motion sensor sends sound waves in air which travels at a speed of 343 m per second at 20 degree. If d be the distance of the reflecting object

total distance travelled = 2d

Time taken t = 8.9 x 10⁻³ s

velocity v  = 2d / t

343 = 2 d / (8.9 x 10⁻³)

d = 1.526 m

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igor_vitrenko [27]

Answer/Explanation:

The mechanical energy is 200 joules. Mechanical energy is determined by adding the total kinetic energy by the total potential energy.

M = kp

100 + 100 = 200

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Toon Train is traveling at the speed of 10 m/s at the top of a hill. Five seconds later it reaches the bottom of the hill and is
Naddika [18.5K]

Answer:

the rate of acceleration of the train is 4 m/s²

Explanation:

Given;

initial velocity of the train, u = 10 m/s

change in time of motion, dt = 5 s

final velocity of the train, v = 30 m/s

The rate of acceleration of the train is calculated as;

a = \frac{dv}{dt} = \frac{v-u}{dt} = \frac{30-10}{5} = \frac{20}{5} = 4 \ m/s^2

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A sinusoidal wave travels along a string. if the time for a particular point to move from maximum displacement to zero displacem
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Define heat...and angle of friction?​
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Read 2 more answers
You are asked to design a spring that will give a 1070 kg satellite a speed of 3.75 m/s relative to an orbiting space shuttle. Y
Dvinal [7]

Answer:

380697.33\ \text{N/m}

0.138\ \text{m}

Explanation:

m = Mass rocket = 1070 kg

v = Velocity of rocket = 3.75 m/s

a = Acceleration of rocket = 5g

g = Acceleration due to gravity = 9.81\ \text{m/s}^2

The energy balance of the system is given by

\dfrac{1}{2}kx^2=\dfrac{1}{2}mv^2\\\Rightarrow kx=\dfrac{mv^2}{x}\\\Rightarrow kx=\dfrac{1070\times 3.75^2}{x}\\\Rightarrow kx=\dfrac{7250}{x}

The force balance of the system is given by

ma=kx\\\Rightarrow m5g=\dfrac{7250}{x}\\\Rightarrow x=\dfrac{7250}{1070\times 5\times 9.81}\\\Rightarrow x=0.138\ \text{m}

The distance the spring must be compressed is 0.138\ \text{m}

k=\dfrac{7250}{x^2}\\\Rightarrow k=\dfrac{7250}{0.138^2}\\\Rightarrow k=380697.33\ \text{N/m}

The force constant of the spring is 380697.33\ \text{N/m}.

4 0
3 years ago
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