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Helga [31]
3 years ago
10

/10

Chemistry
1 answer:
ddd [48]3 years ago
6 0

Explanation:

Uranium-238 undergoes a radioactive decay series consisting of 14 separate steps before producing stable lead-206. This series consists of eight α decays and six β decays.

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Physical science!!! please help
IgorLugansk [536]

Answer:

The correct answer is : No, because there are 4 hydrogen atoms on the reactants side and 2 on the products side.

Explanation:

NH_4NO_3\rightarrow N_2O+H_2O

The given reaction equation is not balanced because:

  • Number of hydrogen atoms  on both sides are not equal that is 4 on reactants side and 2 on products side.
  • Number of oxygen atoms on both sides are not equal that is 3 on reactants side and 2 on products side.

In a balanced chemical equation number of atoms of each elements are equal on both sides.

So, the balanced chemical equation will be:

NH_4NO_3\rightarrow N_2O+2H_2O

7 0
3 years ago
What devices will you use to measure the mass and the volume in this experiment? (density)
bekas [8.4K]

Answer:

Methods for determining or delivering precise volumes include volumetric pipets and pycnometers; less precise methods include burets, graduated cylinders, and graduated pipets. In this experiment, you will measure masses and volumes to determine density. Four different metal cylinders are investigated.

Explanation:

8 0
2 years ago
When hydrogen chloride (HCI) reacts with ammonia (NH3), ammonium chloride (NH4CI) is
givi [52]

Answer:

AMEN NNNNNNNNNNNNNNNNNNNNNNNN

6 0
3 years ago
Select the answers below that represent the ionic compounds in this list: na2so4 h2so4 ch3-ch3 n2o4 cacl2 ca3(po4)2
yarga [219]

Ionic compounds are those compounds which form an ion or dissociates into ions when placed in a solution. These compounds are made up of a metal and non metal. From the choices, here are the ionic compounds:

na2so4

h2so4

cacl2

<span>ca3(po4)2</span>

3 0
3 years ago
How many molecules of H2O are equivalent to 98.2 g of H2O
GREYUIT [131]

Answer:

Demo Mole Quantities

58.5g NaCl(mol/58.5g)(6.02 x 1023/mol) = 6.02 x 1023 Na

+

Cl21 pre-1982 pennies (after 1982 pennies are mostly zinc with copper coating)

63.5g Cu( mol/ 63.5g)(6.02 x 1023/mol) = 6.02 x 1023 Cu

19.0g Al (mol/27.0g)(6.02 x 1023/mol) = 4.24 x 1023 Al

Explanation:

3 0
3 years ago
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