1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
solniwko [45]
2 years ago
6

Convert chloroethane into enene

Chemistry
1 answer:
Solnce55 [7]2 years ago
6 0
Corvette corvette 07
You might be interested in
The mass of a single gold atom is 3.27X10^-22 grams. How many gold Adams with there be in 57.8 mg of gold.
vichka [17]

Answer:

18 * 10^19 atoms

Explanation:

We must first convert 57.8 mg to grams.

If 1000 mg = 1g

  57.8 mg = 57.8/1000 = 57.8 * 10^-3 g

Now;

If 1 gold atom has a mass of 3.27X10^-22 grams

x gold atoms have a mass of 57.8 * 10^-3 g

x = 57.8 * 10^-3 g/3.27X10^-22 g

x = 18 * 10^19 atoms

7 0
3 years ago
Calcium carbonate is the major component of marble .Sulphuric acid is one of the major component of acid rain .write a balanced
lisabon 2012 [21]

Answer:

CaCO3 + H2SO4 ---> CaSO4 + H2O +CO2(gas)

6 0
3 years ago
Na+CL2=2NACL is the balanced reaction for the formation of table salt. Given 20 grams of Na and 10 grams of Cl2, which reactant
Elina [12.6K]

Excess reactant : Na

NaCl produced : = 16.497 g

<h3>Further explanation</h3>

Given

Reaction(balanced)

2Na + Cl₂⇒ 2NaCl

20 g Na

10 g Cl₂

Required

Excess reactant

NaCl produced

Solution

mol Na(Ar = 23 g/mol) :

= 20 : 23 = 0.87

mol Cl₂(MW=71 g/mol):

= 10 : 71 g/mol = 0.141

mol : coefficient :

Na = 0.87 : 2 = 0.435

Cl₂ = 0.141 : 1 = 0.141

Limiting reactant : Cl₂(smaller ratio)

Excess reactant : Na

Mol NaCl based on mol Cl₂, so mol NaCl :

= 2/1 x mol Cl₂

= 2/1 x 0.141

= 0.282

Mass NaCl :

= 0.282 x 58.5 g/mol

= 16.497 g

4 0
2 years ago
In the scientific method, analysis should follow right after
alina1380 [7]
Observation/ question
research
hypothesis
<span>experiment
</span>analysis
conclusion
7 0
2 years ago
How much heat is required, in calories, to raise the temperature of 57.8 g of silver from
Stella [2.4K]

Answer:

87.3 calories of heat is required.

Explanation:

Heat = mcΔT

m= mass, c = specific heat of silver, T = temperature

H= 57.8 g * 0.057 cal/g°C * ( 43.5 - 17 °C)

H = 57.8 * 0.057 * 26.5

H = 87.3069 cal.

The heat required to raise the temperature of 57.8 g of silver from 17 °C to 43.5 °C is 87.3 calories.

8 0
2 years ago
Other questions:
  • An electric circuit can have no current when a switch is ________
    14·2 answers
  • At STP, which 2.0-gram sample of matter uniformly fills a 340-milliliter closed container?
    14·1 answer
  • What type of temperature changes produce large crystals
    14·1 answer
  • Homogeneous mixture that does not settle out upon standing reflect light is an element. solid. hydrated.
    15·1 answer
  • maltase is an enzyme that breaks down maltose. if a maltase enzyme has just completed catalyzing the decomposition of maltose, t
    7·1 answer
  • explain why conductors and insulators are both required to construct the electrical wiring in your home
    5·2 answers
  • How many hydrogen are in 4.02 grams in water​
    9·2 answers
  • What is the density of ethane gas, C2H6 at STP
    5·1 answer
  • CHECK MY RECENT QUESTION HELP ME ASAP
    11·1 answer
  • Where is Convection When you cook a marshmallow on a metal poker tool over an open flame
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!