Cell Differentiation
Giant sequoias can grow more than 80 meters tall! molecules they need for growth using atoms from the water and air around them. ... Plants take in molecules from water and air around them to make different molecules that can be used for energy and growth.
meristematic tissues
<em>-</em><em> </em><em>BRAINLIEST</em><em> answerer</em>
<span>The correct answer for this question would be the S phase of the cell cycle. During the S phase, DNA is synthesised in the form of a complete copy, which is stored in the nucleus, as well as acting as a copy for a microtubule-organising structure referred to as the centrosome.</span>
I think its the c. archaebacteria because there are hundreds of species of archaebacteria living under the sea.....
and bacteria is harmful to all lifes of species..
Answer:
The answer is A.
Explanation:
The inner ear parts are responsible for one of the most important sensory responsibilities in our body which is the keep us in balance and provide us with a sense of stability. It is made of three parts named semicircular canals, vestibule and cochlea.
The structure that contains the receptors mentioned in the question and helps us with our head movements to keep our heads horizontally and vertically in the correct position is called "The Saccule" and it is a part of the vestibule part of the inner ear.
I hope this answer helps.
Answer:
1/8
Explanation:
Given that the trihybrid parents have AaBbCc genotype for fruit color. The trait is a quantitative trait i.e. each dominant allele will have an additive effect on it. In this case, AaBbCc and AABBCC will not produce same fruit color because AaBbCc has only three loci contributing to the color while in AABBCC all the six loci are contributing to the color. For an offspring to be exactly similar to the AaBbCc parents it should have the same genotype of AaBbCc.
The probability of Aa to come from a cross between Aa and Aa is 2/4 or 1/2
The probability of Bb to come from a cross between Bb and Bb is 2/4 or 1/2
The probability of Cc to come from a cross between Cc and Cc is 2/4 or 1/2
So the collective probability of AaBbCc offspring from a cross between AaBbCc and AaBbCc parents would be=
1/2 * 1/2 * 1/2 = 1/8
Hence, assuming no effects of the environment, 1/8 of the offspring will have the same fruit color phenotype as the trihybrid parent.
