What amount of heat absorbs 50 g of steel (ce = 0.115 cal / g. ° C) that
does its temperature vary by 25 ° C?
Answer:
143.75cal
Explanation:
Given parameters:
Mass of steel = 50g
Specific heat capacity of the steel = 0.115cal/g°C
Temperature = 25°C
Unknown:
Amount of heat = ?
Solution:
The amount of heat to cause this temperature change is dependent on mass and specific heat capacity of the substance.
Amount of heat = m C (ΔT)
m is the mass
c is the specific heat capacity
ΔT is the temperature change
Now insert the parameters and solve;
Amount of heat = 50 x 0.115 x 25
Amount of heat = 143.75cal
Answer:
making the decision to buy a lottery ticket
Explanation:
all the others are q result of a thought........whereas the last one is actually one of the thoughts
Answer:
Explanation:
Hello!
In this case, since the equation for the ideal gas is:
For each gas, given the total volume, temperature (28.1+273.15=301.25K) and moles, we can easily compute the partial pressure as shown below:
Best regards!
Answer:
Explanation:
Percent yield is the ratio of the amount actually produced to how much could theoretically be produced. It is found using this formula:
For this reaction, the theoretical or expected yield is 325.0 grams. The actual yield is 123.8 grams.
Divide.
Round to the nearest hundredth. The 9 in the hundredth place tells us to round the 0 to a 1 .
The percent yield is about <u>38.1%</u>
Answer:
Mass of compound = 0.24 g and, mass of boron = 0.096 g percentage of boron in the compound = mass of boron / mass of compound * 100 = 0.096/0.24 * 100 = 40% mass of oxygen = 0.144 g again, mass of compound = 0.24 g percentage of oxygen in compound = mass of oxygen/mass of of compound * 100 = 0.144/0.24 * 100 = 60%
<h2>Hope it's Helpful!!✌️</h2>
