Answer:
The amount of energy liberated will be 49.38 J.
Explanation:
The amount of energy liberated (gibbs free energy) can be calculated using the following equation:
ΔG° = -nFε
n: amount of moles of electrons transfered
F: Faraday's constant
ε: cell potential
20.0 g of Zn is equal to 0.30 mol.
Two electrons are transfered during the reaction.
Therefore, n = 2x0.30 ∴ n = 0.60
ΔG° = - 0.60 x 96.485 x 0.853
ΔG° = 49.38 J
Answer:
The minimum concentration of acetaminophen that can be detected by new= 10μg/mL
Volume of blood sample=2ml
Minimum mass of acetaminophen that can be detected by automated system= 10×2= 20μg= 0.020mg
I think your answer will be B. 273 k
