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2 years ago

GUYS HELP!!! I NEED MY BATTERY TO LAST 3 MORE HOURS, AND ITS AT 1%!!!!!!!!!!!!!!!! HELPPP

Mathematics

2 answers:

Alja [10]2 years ago

7 0

Answer:

plug in your charger- or put it on low power mode/ turn down the brightness

ololo11 [35]2 years ago

3 0

GET A CHARGER PLUG IT ON A SOCKET THEN BOOM!!!!!...........BUT Seriously if your using apple press low battery mode

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What is the equation of this graphed line?

xz_007 [3.2K]

Answer is highlighted in blue. If you have any questions feel free to ask.

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2 years ago

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Kristin spent $131 on shirts. Fancy shirts cost $28 and plain shirts cost $15. If she bought a total of 7 shirts then how many o

KIM [24]

Answer:

Kristin bought 5 plain shirts and 2 fancy shirts.

Hope this helps!

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3 years ago

A cable car starts off with n riders. The times between successive stops of the car are independent exponential random variables

nikitadnepr [17]

Answer:

The distribution is $\frac{\lambda^{n}e^{- \lambda t}t^{n - 1}}{(n - 1)!}$

Solution:

As per the question:

Total no. of riders = n

Now, suppose the $T_{i}$ is the time between the departure of the rider i - 1 and i from the cable car.

where

$T_{i}$ = independent exponential random variable whose rate is $\lambda$

The general form is given by:

$T_{i} = \lambda e^{- lambda}$

(a) Now, the time distribution of the last rider is given as the sum total of the time of each rider:

$S_{n} = T_{1} + T_{2} + ........ + T_{n}$

$S_{n} = \sum_{i}^{n} T_{n}$

Now, the sum of the exponential random variable with $\lambda$ with rate $\lambda$ is given by:

$S_{n} = f(t:n, \lamda) = \frac{\lambda^{n}e^{- \lambda t}t^{n - 1}}{(n - 1)!}$

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3 years ago

Use long division to convert -45/8 to a decimal.

Olenka [21]

The answer is A. -5.625

7 0

3 years ago

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Please Help !! Show All Work !!

GrogVix [38]

Answer:

1) (4,4) 2) (4,0) 3) (6,1)

Step-by-step explanation:

$(\frac{5+13}{2} )(\frac{7+1}{2} )\\(\frac{8}{2} )(\frac{8}{2} )\\(4,4)$

$(\frac{-3+7}{2} )(\frac{-3+3}{2} )\\(\frac{4}{2} )(\frac{0}{2} )\\(4,0)$

$\frac{-5+x_2}{2} =1$ multiply 1 by 2=2 then write $(+5)-5+x_2=1(+5)\\x_2 = 6$

$\frac{3+y_2}{2} =2$ multiply 2 by 2= 4 then write $(-3)3+y_2=4(-3)\\y_2=1$

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3 years ago