Answer:
n > 5
Step-by-step explanation:
<u>Solution-</u>
From the figure,
AE = 2.4
EB = 2.8
BC = 11.7
Area of rectangle 1 = 8.68 sq.in

(∵ sides of the rectangle 2)
Area of Triangle 1 = 6.48 sq.in


(∵ sides of the rectangle 1)


(∵ sides of the rectangle 2)



The area of Rectangle 2,

The area of Triangle 2,

The area of the whole figure = Area of Triangle 1 + Area of rectangle 1 + Area of Triangle 2 + Area of rectangle 2
= 6.48+8.68+8.82+6.44=30.42 sq.in
Answer:
Radius of the circle = 119
Step-by-step explanation:
here's the solution :-
we know that the perpendicular from centre to any chord bisects the chord so,
=》AT = 1/2 × OT
=》AT = 1/2 × 210
=》AT = 105
now, join VT ( by construction )
so, triangle VTA is a right angled triangle, with right angle on A.
now, by pythagorous theorem,
=》VT^2 = VA^2 + AT^2
=》VT^2 = (56)^2 + (105)^2
=》VT^2 = 3136 + 11025
=》VT =

=》VT = 119
and VT joins the centre of the circle with the circumference, hence VT is the radius of the circle .
5x+70=320 I think that might be it tell me if its wrong