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Ostrovityanka [42]
3 years ago
15

when a charge of 1 C has an electric PE of 1 J, it has an electric potential of 1 V. When a charge of 2 C has an electric PE of

2 J, it's potential is?
Physics
1 answer:
matrenka [14]3 years ago
7 0
1 volt. 
1/1 = 1
2/2 = 1
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Ian walks 2 km to his best friends house, then walks 0.5 km to the library. He then makes 2.5 km walk home. The entire walk took
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9. A balloon is filled with 1000 cm3 of a gas weighing 1000 g. Will it rise or fall when it is released?
torisob [31]

We can calculate the density of the balloon as follows:

\rho=\frac{mass}{volume}=\frac{1000g}{1000cm^3}=\frac{1g}{cm^3}

Therefore, the balloon will fall

Since the density of air is about 0.00123 g/cm^3 , the balloon is much more dense than the surrounding air. As a result, the balloon weighs more than the air that it displaces so the balloon will fall.

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1 year ago
A cricket starts at the 5 meter mark on a ruler. It jumps to the 10 meter mark. Then, it jumps back to the 6 meter mark. Calcula
belka [17]

We have that the cricket’s displacement is  

D_t=9meters

From the Question we are told that

Start position  5 meter mark

It jumps to the 10 meter mark.

it jumps back to the 6 meter mark.

Generally the equation for cricket’s displacement. is mathematically given as

D_t=Initial +final(displacement)\\\\D_t=(10-5)+(10-6)

D_t=9meters

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What do you mean by specific heat capacity?​
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2 years ago
Two workers are sliding 390 kg crate across the floor. One worker pushes forward on the crate with a force of 450 N while the ot
weeeeeb [17]

Answer:

The coefficient of kinetic friction \mu= 0.16989

Explanation:

From Newton's second law

\sum\overset{\rightarrow}{F}=m\cdot\overset{\rightarrow}{a}

If the velocity is constant, that means the summation of all forces must be equal to zero. Draw the free-body diagram to obtain the sums of forces in x and y. It must include the Friction Force, in the opposite direction of the displacement, the weight (W=mg=390*9.81=3825.9N), the Normal Force, which is the is the consequence of Newton's third law and the forces from the two workers.

The sum in y is:

\sum F_{y}=F_{N}-3825.9=0

Solving for the F_{N}:

F_{N}=$ $3825.\,\allowbreak9N

The sum in x is:

\sum F_{x}=450+200-F_{f}=0

Solving for the F_{f}:

$F_{f}=650.0N

The formula of the magnitude of the Friction force is

F_{f}=\mu F_{N}

That means the coefficient of friction is:

\mu=\frac{F_{f}}{F_{N}}=\frac{650.0}{3825.\,\allowbreak9}=\allowbreak0.16989

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2 years ago
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