1. 2+0.5+2.5= 3. 2km/hr average
2. 14-6=4seconds. 8m/s in 4s = 2m/s acceleration
3. 15m/s divided by 2.5 = 6m/s acceleration
We can calculate the density of the balloon as follows:

Therefore, the balloon will fall
Since the density of air is about 0.00123 g/cm^3 , the balloon is much more dense than the surrounding air. As a result, the balloon weighs more than the air that it displaces so the balloon will fall.
We have that the cricket’s displacement is

From the Question we are told that
Start position 5 meter mark
It jumps to the 10 meter mark.
it jumps back to the 6 meter mark.
Generally the equation for cricket’s displacement. is mathematically given as


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Answer:
The coefficient of kinetic friction 
Explanation:
From Newton's second law

If the velocity is constant, that means the summation of all forces must be equal to zero. Draw the free-body diagram to obtain the sums of forces in x and y. It must include the Friction Force, in the opposite direction of the displacement, the weight (
), the Normal Force, which is the is the consequence of Newton's third law and the forces from the two workers.
The sum in y is:

Solving for the
:

The sum in x is:

Solving for the
:

The formula of the magnitude of the Friction force is

That means the coefficient of friction is:
