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2 years ago

Please help me solve this:

Mathematics

1 answer:

kirill115 [55]2 years ago

3 0

Answer:

$\frac{y_2-y_2}{x_2-x_1}=m=\frac{-5-3}{1_(_1)} \\ m=-\frac{8} {2}=-4\\ \frac{y-y_1}{x-x_1}=m\\ \fracp{y-3}{x+1}=-4\\y-3=-4(x+1)\\ y-3=-4x-4\\y=-4x-1$

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sp2606 [1]

Answer:

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Step-by-step explanation:

sin θ = 21/29

Use Pythagorean identity:

sin² θ + cos² θ = 1

(21/29)² + cos² θ = 1

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cos² θ = 400/841

cos θ = ±20/29

Since 0° < θ < 90°, cos θ > 0. So cos θ = 20/29.

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Answer:

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Step-by-step explanation:

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