Question

Please help me solve this:

Answer 1

Answer:

$\frac{y_2-y_2}{x_2-x_1}=m=\frac{-5-3}{1_(_1)} \\ m=-\frac{8} {2}=-4\\ \frac{y-y_1}{x-x_1}=m\\ \fracp{y-3}{x+1}=-4\\y-3=-4(x+1)\\ y-3=-4x-4\\y=-4x-1$