Answer:
The correct option is
C) Trial 1 will have the same calculated empirical formula as trial 2.
Explanation:
The empirical formula is the formula of a chemical compound that states the simplest whole number ratio of each of the atoms included in the compound. It is obtained by dividing the mass of an element present in the compound by the element's molar mass to find the mole ratio of the elements. The obtained mole value for each element is then divided by the smallest number of moles obtained in the division.
By definition the composition and ratio of elements combined in a chemical compound is fixed, therefore trial 1 will have the same calculated empirical formula as trial 2.
K2MnO4+(2)H2O —>KMnO4+(2)KOH+(2)H2
Coefficients are in parentheses and subscripts are just normal letters
A covalent bond is a chemical bond that involves the sharing of electron pairs between atoms. These electron pairs are known as shared pairs or bonding pairs, and the stable balance of attractive and repulsive forces between atoms, when they share electrons, is known as covalent bonding.
Answer:
1. Mixture
2. Compound
3. Compound
4. Element
Explanation:
Number 1 shows two completely different types of compounds in the same space, so it is a mixture.
Numbers 2 and 3 are compounds because there aren't different types compounds as in Number 1, but the same compound repeated. 2 is a compound because while all of the circles are the same element, they are connected. O2 for example, oxygen, is a compound.
Number 4, finally, is all of the same substance, non-connected, so it shows an element.
Brainliest, please :) (Trying to become a genius so that I can continue helping more people)
<span>Well # # Drops of Iron Sulfate # Drops of Sodium Hydroxide
</span><span> A1 5 45
A2 10 40
A3 15 35
A4 20 30
A5 25 25
A6 30 20
B1 35 15
B2 40 10
B3 45 5
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<span>that's for B, because it says "Iron Sulfate".
which is this equation:
FeSO4 (aq) + 2NaOH (aq) Fe(OH)2 (s) + Na2SO4 (aq)
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<span>FeSO4 (aq) + 2NaOH (aq) Fe(OH)2 (s) + Na2SO4 (aq)
ratio of FeSO4:NaOH is 1:2,
so you need to moles of NaOH for every mole of FeSO4.
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<span>A1-A6 had precipitate, though less ppt every time.
This corresponds to the decrease in the number of NaOH drops
At A2 10/1:40/2 the stoichiometric ratio is equal, so you should've seen the post ppt present. But looking at the picture it doesn't look right. I think you might've labelled them wrong, or there is an error somewhere. This fits micro-plate A better.</span><span>
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