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2 years ago

6/23-15/127 as an improper fraction

Mathematics

1 answer:

Lina20 [59]2 years ago

6 0

Answer:

417/2921

Step-by-step explanation:

6/23-15/127

- First, we have to figure out the lcm which is 2921.

- Multiply the denominators so make them 2921.

(127) 6/23 - 15/127(23)

762/2921 - 345/2921

- Subtract the numerators.

417/2921

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Answer:

Following are the solution to the given points:

Step-by-step explanation:

$X = \text{cost of wedding}\sim \text{Normal}\ (\mu = 28732, \sigma= 1500)\\\\$

For point a:

$Probability\ = 0.00000359\\\\ \text{(Using Excel function:} =NORMDIST(22000,28732,1500,1)).$

For point b:

$Probability \ = 0.014678\\\\\text{(Using Excel function:} =1-NORMDIST(32000,28732,1500,1))\\\\$

For point c:

$Probability\ = 0.794614436 \\\\$

$\text{(Using Excel function:} \\=NORMDIST (30000,28732,1500,1)-NORMDIST(25000,28732,1500,1))\\\\$

For point d:

$Q_1 = 27720.26537 \\\\\text{(Using Excel function:} =NORMINV(0.25,28732,1500)) \\\\Q_3 = 29743.73463 \\\\\text{(Using Excel function:} =NORMINV(0.75,28732,1500)).$

For point e:

$IQR = Q_3 - Q_1 = 29743.73463 - 27720.26537 = 2023.469251.$

For point f:

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