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Elanso [62]
3 years ago
5

How does camouflage help organisms in its habitat​

Chemistry
1 answer:
otez555 [7]3 years ago
4 0

Answer:

so I can hide from predators on not be eaten. or so it can sneak up on its prey

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The iupac name of this ??
Licemer1 [7]
Methylhexanamine<span> and its formula is C7H17N</span>
that thing is a drug
3 0
3 years ago
a baseball player hits a baseball with a bat.The mass of the ball is 0.25kg.The ball accelerates at 200m/s2
34kurt

Answer:

50N

Explanation:

Force (N) = mass (kg) × acceleration (m/s²)

0.25kg times 200m/s² = 50N

5 0
3 years ago
How do i know if a reaction is exo/endothermic?? help please.
goblinko [34]

Answer:

Explanation: in exothermic reaction heat is released out

In endothermic reaction heat is absorbed

3 0
3 years ago
Assuming all the NH3 dissolves and that the volume of the solution remains at 0.450 L , calculate the pH of the resulting soluti
Yanka [14]

Answer:

8.9357.

Explanation:

So, let us dive right into the solution to the above problem;

We have that the volume of the solution = 0.450 L.

The first thing to do is to determine the number of moles by using the formula below:

Pressure × volume = number of moles × gas constant × temperature.

Therefore, making the number of moles the subject of the formula we have;

Number of moles = (pressure × volume)/ has constant × temperature.

Number of moles of NH3=( 735 × 7.50 )/ 62.4 × 295 = 0.2995 moles.

The number of moles of HCl =

0.450 × 0.450 = 0.2025 moles.

Molarity of HCl = 0.2025 moles/ 0.450 L = 0.45M.

The molarity of {OH^-} = (0.2995 moles - 0.2025 moles) /0.450 = 0.097/0.450 = 0.2156 M.

Therefore, kb = 1.8 × 10^-5 = [ 0.450] [OH^-] / [ 0.2156 M] = 0.000008624.

[OH^-] = 0.000008624.

Hence, pOH = 5.0643.

pH = 14 - 5.0643 = 8.9357.

6 0
3 years ago
What role does temperature play in the growth of bacteria?
Georgia [21]

Answer:

Every bacterial species has specific growth temperature requirements which is largely determined by the temperature requirements of its enzymes.

<h3>Hope this helps..</h3>
5 0
3 years ago
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