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AveGali [126]
3 years ago
14

How many ions are present in 75.0g of magnesium sulfate

Chemistry
1 answer:
Ostrovityanka [42]3 years ago
4 0

Answer:

7.5×10²³ ions

Explanation:

Given data:

Mass of magnesium sulfate = 75.0 g

Number of ions = ?

Solution:

Number of moles of magnesium sulfate:

Number of moles = mass/molar mass

Number of moles = 75.0 g/ 120.36 g/mol

Number of moles = 0.623 mol

Magnesium sulfate formula: MgSO₄

Number of moles of ions in 1 mole of MgSO₄ = 2 mol (Mg²⁺ and SO₄²⁻)

Number of moles of ion in 0.623 moles of MgSO₄:

2 mole ×0.623 = 1.246 mol

Number of ions:

1 mole contain 6.022×10²³ ions

1.246 mol × 6.022×10²³ ions / 1mol

7.5×10²³ ions

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Balanced equation:
2 Fe₂O₃ + 3 C → 4 Fe + 3 CO₂
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When magnesium hydroxide reacts with nitric acid, it produces magnesium nitrate and water
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A gas is at a pressure of 12.5 psi and a volume of 750 mL. What volume will the gas occupy at a pressure of 18 psi?
sergij07 [2.7K]

Answer : The volume of gas occupy at a pressure of 18 psi is, 520.8 mL

Explanation :

Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

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