Question

How many ions are present in 75.0g of magnesium sulfate

Answer 1

Answer:

7.5×10²³ ions

Explanation:

Given data:

Mass of magnesium sulfate = 75.0 g

Number of ions = ?

Solution:

Number of moles of magnesium sulfate:

Number of moles = mass/molar mass

Number of moles = 75.0 g/ 120.36 g/mol

Number of moles = 0.623 mol

Magnesium sulfate formula: MgSO₄

Number of moles of ions in 1 mole of MgSO₄ = 2 mol (Mg²⁺ and SO₄²⁻)

Number of moles of ion in 0.623 moles of MgSO₄:

2 mole ×0.623 = 1.246 mol

Number of ions:

1 mole contain 6.022×10²³ ions

1.246 mol × 6.022×10²³ ions / 1mol

7.5×10²³ ions