There are 14 atoms, the 2 at the front times' everything by 2, so there 4Ks, 2Ss and 8Os, altogether 14
Answer:
yesakskakakakakakkawbajajjakaak
Answer: Raw data, perhaps.
Explanation: I'm not certain what the question is seeking for an answer, but I would suggest "raw data" would be a reasonable choice. It reflects the data was recorded, but not yet processed to provide a conclusion or observation.
If one were a bit snarky, other possiblities include
- a pile of dung
- my labmate's scrawls, or
- the best web results I could find
Answer:
CH4
Explanation:
In solving this problem, we must remember that one mole of a compound contains Avogadro's number of elementary entities. These elementary entities include atoms, molecules, ions etc. Recall that one mole of a substance is the amount of substance that contains the same number of elementary entities as 12g of carbon-12. The Avogadro's number is 6.02 × 10^23.
Hence we can now say;
If 163 g of the compound contains 6.13 ×10^24 molecules
x g will contain 6.02 × 10^23 molecules
x= 163 × 6.02 × 10^23 / 6.13 × 10^24
x= 981.26 × 10^23/ 6.13 ×10^24
x= 160.1 × 10^-1 g
x= 16.01 g
x= 16 g(approximately)
16 g is the molecular mass of methane hence x must be methane (CH4)
