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3 years ago

A crow flies 100 meters east in 5 minutes. What is the crow’s velocity?

Chemistry

1 answer:

torisob [31]3 years ago

3 0

Answer: 20 m/min east

Explanation: The speed is distance divided by time

distance between start-point and end-point = 100 meters

time to cover the distance = 5 minutes

100 m ÷ 5 min = 20 m/min east

you have to add east since velocity is the measure of speed and direction and your answer needs to include the direction

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Would an element with 7 valence electrons be more or less reactive than an element with 3 valence electrons?

Sedbober [7]

Answer:

That would be more

Explanation:

5 0

4 years ago

Which reaction will occur? 2NaBr I2 Right arrow. 2NaI Br2 2Fe Al2O3 Right arrow. 2Al Fe2O3 2AgNO3 Ni Right arrow. Ni(NO3)2 2Ag P

Likurg_2 [28]

The reaction that has been occurred will be $\rm 2\;Fe\;+\;Al_2O_3\;\rightarrow\;2\;Al\;+\;Fe_2O_3$ .

The chemical reaction has been defined as the interaction of the reactant molecules for the formation of the product. The changes have been taken place in the reactivity series and under specific conditions.

<h3>Reaction occur</h3>

The displacement reaction has been taken place based on the reactivity series. The more reactive element has been able to displace the less reactive element in the compound and form a new compound.

The following reactions have been analyzed as:

$\rm 2\;NaBr\;+\;I_2\;\rightarrow\;2\;NaI\;+\;Br_2$

In the reaction, Br has been replaced by Iodine. The iodine has been less reactive than Br and thus will not form the compound.

Thus, this reaction will not occur.

$\rm 2\;Fe\;+\;Al_2O_3\;\rightarrow\;2\;Al\;+\;Fe_2O_3$

In the reaction, Al has been replaced by Fe. The Fe is more reactive than Al. thus this reaction will occur.

$\rm 2\;AgNO_3\;+\;Ni\;\rightarrow\;Ni(NO_3)_2\;+\;2\;Ag$

The nickel has been less reactive than Ag, and thus will not be able to form the product.

Thus, this reaction will not occur.

$\rm Pb\;+\;Zn(C_2H_3O_2)_2\;\rightarrow\;Zn\;+\;Pb(C_2H_3O_2)_2$

The lead has been less reactive than Zn, and thus will not be able to form the product.

Thus, this reaction will not occur.

The reaction that has been occurred will be $\rm 2\;Fe\;+\;Al_2O_3\;\rightarrow\;2\;Al\;+\;Fe_2O_3$ .

Learn more about reactivity series, here:

brainly.com/question/10443908

8 0

3 years ago

How much carbon dioxide will be formed if 12.5 grams of oxygen reacts with 7.2 grams of propane (C3H8 )? Balanced equation: C3H8

solong [7]

Answer:

10.3125 grams of carbon dioxide will be formed.

Explanation:

The balanced reaction is:

C₃H₈ + 5 O₂→ 3 CO₂ + 4 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles participate in the reaction:

C₃H₈: 1 mole
O₂: 5 moles
CO₂: 3 moles
H₂O: 4 moles

Being the molar mass of the compounds:

C₃H₈: 44 g/mole
O₂: 32 g/mole
CO₂: 44 g/mole
H₂O: 18 g/mole

then by stoichiometry of the reaction, the following amounts of mass participate in the reaction:

C₃H₈: 1 mole* 44 g/mole = 44 g
O₂: 5 moles* 32 g/mole= 160 g
CO₂: 3 moles* 44 g/mole= 132 g
H₂O: 4 moles* 18 g/mole= 72 g

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

To determine the limiting reagent, it is possible to use a simple rule of three as follows: If by reaction stoichiometry 44 grams of propane react with 160 grams of oxygen, 7.2 grams of propane react with how much mass of oxygen?

$mass of oxygen=\frac{7.2 grams of propane*160 grams of oxygen}{44 grams of propane}$

mass of oxygen= 26.18 grams

But 26.18 moles of O₂ are not available, 12.5 grams are available. Since you have less mass than you need to react with 7.2 grams of propane, oxygen O₂ will be the limiting reagent.

Then you can apply the following rule of three: if by stoichiometry of the reaction 160 grams of oxygen form 132 grams of carbon dioxide, 12.5 grams of oxygen will form how much mass of carbon dioxide?

$mass of carbon dioxide=\frac{12.5 grams of oxygen*132 grams of carbon dioxide}{160 grams of oxygen}$