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3 years ago

12

Which of the following are dependent events?

1 answer:

kotykmax [81]3 years ago

4 0

The best answer is B im sorry if its wrong but im sure its B

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Step 1: Use equations to solve problems.

Crazy boy [7]

Answer:

Step-by-step explanation:

6 0

3 years ago

Question shown in pic attached!

m_a_m_a [10]

Answer: <B= 101, <C= 79, <D=101

Step-by-step explanation: all parallelograms have the diagonal angles equal so that is why <c=79. Parallelograms also have all angles equal to 360. so if you add <C, and <A you have 158. then you subtract that from 360 and you get 202. You then need to divide it by to to get the measures of angles B and D which are 101 each.

8 0

3 years ago

Solve the equation: <br> 8x + 6 – 9x = 2 - X + 4

nataly862011 [7]

8x+6-9x= 2-x+4
8x+6+-9x=2+-x+4
(8x + -9x) + (6) = (-x) + (2+4) (combine like terms)
-x+6= -x+6
-x+6+x=-x+6+x
6-6=6-6
0=0

4 0

3 years ago

(-8,-4)&(2,-9) fint the distance between each pair of points

Makovka662 [10]

Answer:

$5 \sqrt{5}$

Step-by-step explanation:

We want to find the distance between (-8,-4) and (2,-9).

We use the distance formula:

$d = \sqrt{ {(x_2-x_1)^2} +(y_2-y_1)^2 }$

We substitute the coordinates to get:

$d = \sqrt{ {(2- - 8)^2} +( - 9 - - 4)^2 }$

We simplify to obtain:

$d = \sqrt{ {(2 + 8)^2}+( - 9 + 4)^2 }$

Add the numbers within the parenthesis to get:

$d = \sqrt{ {(10)^2}+( -5)^2 }$

Find the squares of the numbers under the radical

$d = \sqrt{ {100}+25}$

$d = \sqrt{125} = 5 \sqrt{5}$

7 0

3 years ago

Colton has 8 comedy movies, 6 action movies, 555 fantasy movies, and 1 drama movie on his list of favorite movies.

11Alexandr11 [23.1K]

Answer:

The correct option is A.

Step-by-step explanation:

It is given that Colton has 8 comedy movies, 6 action movies, 5 fantasy movies, and 1 drama movie on his list of favorite movies.

Total number of favorite movies is

$8+6+5+1=20$

Therefore Colton has 20 movies in the list of favorite movies.

For every 5 movies on the list, there are 2 movies of required category.

$\frac{2}{5}\times \frac{4}{4}=\frac{8}{20}$

For every 20 movies on the list, there are 8 movies of required category.

Out of 20 movies we have 8 comedy movies, therefore the required category is comedy movie.

The ratio of comedy movie and total movies is

$\frac{8}{20}=\frac{2}{5}$

Therefore we can say that for every 5 movies on the list, there are 2 comedy movies. Option A is correct.

8 0

3 years ago

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