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3 years ago

Table to estimate how many pounds of dog food his dog eat in one year which of the following would be the best strategy

Mathematics

1 answer:

Usimov [2.4K]3 years ago

3 0

Let's say that the dogs eat 50 lbs of food in 50 days. That would mean they eat 50/50 = 1 pound per day. Notice I divided the weight over the number of days. The dog eats 1 pound per day, for 365 days, so in total it eats 365*1 = 365 pounds. This is just a hypothetical example.

In general, if x is the number of days to eat 50 pounds of food, then x/50 is the expression representing the amount eaten per day (in pounds). Finally 365*(x/50) is the expression representing the total amount eaten over the whole year.

This is why the final answer is choice C

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1 year ago

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bija089 [108]

Answer:

a) {2/n²-7/n+9}/{8+2/n-6/n²}

b) 9/8

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Step-by-step explanation:

Given the limit of the function

limn→[infinity]2−7n+9n²/8n²+2n−6

To simplify the function given, we will have to factor out the highest power of n which is n² from the numerator and the denominator. The function will then become;

2−7n+9n²/8n²+2n−6

= n²{2/n²-7/n+9}/n²{8+2/n-6/n²}

The n² at the numerator will then cancel out the n² at the denominator to have resulting simplified equation as;

{2/n²-7/n+9}/{8+2/n-6/n²}

Evaluating the limit of the resulting equation will give;

limn→[infinity] {2/n²-7/n+9}/{8+2/n-6/n²}

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Therefore;

limn→[infinity] {2/n²-7/n+9}/{8+2/n-6/n²}

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= 9/8

Since the limit of the sequence gives a finite value which is 9/8, thus the sequence in question is a convergent sequence.

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