The objective function is simply a function that is meant to be maximized. Because this function is multivariable, we know that with the applied constraints, the value that maximizes this function must be on the boundary of the domain described by these constraints. If you view the attached image, the grey section highlighted section is the area on the domain of the function which meets all defined constraints. (It is all of the inequalities plotted over one another). Your job would thus be to determine which value on the boundary maximizes the value of the objective function. In this case, since any contribution from y reduces the value of the objective function, you will want to make this value as low as possible, and make x as high as possible. Within the boundaries of the constraints, this thus maximizes the function at x = 5, y = 0.
Answer: 105 and angel 2 are alternate exterior angles, angle 2 is 105 degrees. Angles 1 and 2 and supplementary so 180-105 is 75. Angle 1 measures 75 degrees.
Step-by-step explanation:
The answer is A.
Answer:10,800
Step-by-step explanation:
im not sure but what i did was 90x120=10800
Kade worked for 15 hours and theo worked for 12
Answer:

Step-by-step explanation:
Factorize:

<u>Factor Theorem</u>
If f(a) = 0 for a polynomial then (x - a) is a factor of the polynomial f(x).
Substitute x = 1 into the function:

Therefore, (x - 1) is a factor.
As the polynomial is cubic:

Expanding the brackets:


Comparing coefficients with the original polynomial:



Therefore:

Cannot be factored any further.