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3 years ago

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If f (x) = x2 - x, what is f(6)?

1 answer:

nataly862011 [7]3 years ago

6 0

Answer:

$f(x) = {x}^{2} - x \\ f(6) = {6}^{2} - 6 \\ = 36 - 6 = 30$

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Find the values of m and b for this line.

Andrej [43]

Answer:

b=-5, m= - 3/-2

Step-by-step explanation:

Slope equation is y=mx+b. Slope is finding the rise(vertical change) over run(horizontal change). In this case, -3 is our negative rise and 2 is our run. Put that into fraction form, we get negative 3/2. In the slope equation, b represents the y-intercept(where the line touches the y-axis). In this case, it is -5. Hope this helps you!

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2 years ago

The function f(x) = x2 + 6x + 3 is transformed such that g(x) = f(x − 2). Find the vertex of g(x).

garri49 [273]

Answer:

(-1,-6)

Step-by-step explanation:

$f(x)=x^2+6x+3$

$g(x)=f(x-2)$

$g(x)=(x-2)^2+6(x-2)+3$ (Replaced x in f with (x-2))

$g(x)=x^2-4x+4+6x-12+3$ (Used $(x+b)^2=x^2+2bx+b^2$ and distributive property)

$g(x)=x^2-4x+6x+4-12+3$ (Gathered like terms)

$g(x)=x^2+2x-5$ (Simplified)

The vertex of a parabola occurs at $(\frac{-b}{2a},g(\frac{-b}{2a})$ .

Let's find $\frac{-b}{2a}$ first.

$\frac{-2}{2(1)}=-1$

Now we can obtain $g(\frac{-b}{2a})$ which is $g(-1)$ in this case:

$g(x)=x^2+2x-5$

$g(-1)=(-1)^2+2(-1)-5$

$g(-1)=1-2-5$

$g(-1)=-1-5$

$g(-1)=-6$ .

The vertex is (-1,-6).

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Step-by-step explanation:

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3 years ago

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4 years ago

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jarptica [38.1K]

Answer:

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Step-by-step explanation:

Add the x and y values separately which is across from your screen to get the function which is (-7, 1).

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