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castortr0y [4]
3 years ago
8

Solve the system using substitution: y = -6x + 7 3x – 2y = 16 helppp

Mathematics
2 answers:
bearhunter [10]3 years ago
7 0

Answer:

x=-6 y=-1

Step-by-step explanation:

// Solve equation [2] for the variable  y  

 

 [2]    y = -x - 7

// Plug this in for variable  y  in equation [1]

  [1]    3x - 2•(-x -7) = -16

  [1]    5x = -30

// Solve equation [1] for the variable  x  

  [1]    5x = - 30  

  [1]    x = - 6  

// By now we know this much :

   x = -6

   y = -x-7

// Use the  x  value to solve for  y  

   y = -(-6)-7 = -1  

Solution :

{x,y} = {-6,-1}

marissa [1.9K]3 years ago
6 0

Answer: 1 .x=-1/6y+7/6 (2.x=2/3y+16/3

Step-by-step explanation:

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8 0
3 years ago
Which shows the following expression after the negative exponents have been eliminated? xy^-6/x^-4 y^2, x=/0 y=/0
makvit [3.9K]
The expression would be \frac{x^5}{y^8} after the negative exponents have been removed.

A negative exponent basically tells us to "flip" the side of the fraction it's on.  This means that y⁻⁶ on the numerator would go to the denominator, and that x⁻⁴ on the denominator would go to the numerator.  This gives us:

\frac{x\times x^4}{y^2\times y^6}=\frac{x^5}{y^8}
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3 years ago
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2 years ago
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6 0
3 years ago
Substitute this equation x+3y=18 &amp; -x-4y=-25
sveticcg [70]

Answer:

 {x,y} = {3/7,-43/7}

Step-by-step explanation:

System of Linear Equations entered :

  [1]    x + 3y = -18

  [2]    -x + 4y = -25

Graphic Representation of the Equations :

   3y + x = -18        4y - x = -25  

 

 

Solve by Substitution :

// Solve equation [1] for the variable  x  

 

 [1]    x = -3y - 18

// Plug this in for variable  x  in equation [2]

  [2]    -(-3y-18) + 4y = -25

  [2]    7y = -43

// Solve equation [2] for the variable  y  

  [2]    7y = - 43  

  [2]    y = - 43/7  

// By now we know this much :

   x = -3y-18

   y = -43/7

// Use the  y  value to solve for  x  

   x = -3(-43/7)-18 = 3/7  

Solution :

{x,y} = {3/7,-43/7}

5 0
3 years ago
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