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3 years ago

Solve the system using substitution: y = -6x + 7 3x – 2y = 16 helppp

Mathematics

2 answers:

bearhunter [10]3 years ago

7 0

Answer:

x=-6 y=-1

Step-by-step explanation:

// Solve equation [2] for the variable y

[2] y = -x - 7

// Plug this in for variable y in equation [1]

[1] 3x - 2•(-x -7) = -16

[1] 5x = -30

// Solve equation [1] for the variable x

[1] 5x = - 30

[1] x = - 6

// By now we know this much :

x = -6

y = -x-7

// Use the x value to solve for y

y = -(-6)-7 = -1

Solution :

{x,y} = {-6,-1}

marissa [1.9K]3 years ago

6 0

Answer: 1 .x=-1/6y+7/6 (2.x=2/3y+16/3

Step-by-step explanation:

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wlad13 [49]

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8 0

3 years ago

Which shows the following expression after the negative exponents have been eliminated? xy^-6/x^-4 y^2, x=/0 y=/0

makvit [3.9K]

The expression would be $\frac{x^5}{y^8}$ after the negative exponents have been removed.

A negative exponent basically tells us to "flip" the side of the fraction it's on. This means that y⁻⁶ on the numerator would go to the denominator, and that x⁻⁴ on the denominator would go to the numerator. This gives us:

$\frac{x\times x^4}{y^2\times y^6}=\frac{x^5}{y^8}$

4 0

3 years ago

Read 2 more answers

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kotegsom [21]

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5 0

2 years ago

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juin [17]

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6 0

3 years ago

Substitute this equation x+3y=18 & -x-4y=-25

sveticcg [70]

Answer:

{x,y} = {3/7,-43/7}

Step-by-step explanation:

System of Linear Equations entered :

[1] x + 3y = -18

[2] -x + 4y = -25

Graphic Representation of the Equations :

3y + x = -18 4y - x = -25

Solve by Substitution :

// Solve equation [1] for the variable x

[1] x = -3y - 18

// Plug this in for variable x in equation [2]

[2] -(-3y-18) + 4y = -25

[2] 7y = -43

// Solve equation [2] for the variable y

[2] 7y = - 43

[2] y = - 43/7

// By now we know this much :

x = -3y-18

y = -43/7

// Use the y value to solve for x

x = -3(-43/7)-18 = 3/7

Solution :

{x,y} = {3/7,-43/7}

5 0

3 years ago