All categories

2 years ago

Need help!

Chemistry

1 answer:

inysia [295]2 years ago

5 0

Answer:

When an apple is cut or bruised the oxygen goes into the injured plant tissue. It begins to oxidize from the reaction of the enzymes and oxygen. The apple produces melanin to protect it causing it to brown. Using vinegar and lemon juice help stop the browning because lemon juice has a compound that reacts with oxygen before the oxygen can react with apple. Also, vinegar and lemons are very acidic which slows the browning reaction.

I tried :<

You might be interested in

Trying to explain why a cactus needs little water to survive is an example of

zmey [24]

It’s a or b i think it’s b

6 0

2 years ago

HELPP ANSWERSSS!!!!

dusya [7]

Answer:

answer is

Explanation:

Gallium because it has the properties which you have mentioned

8 0

2 years ago

The Surface of Earth is changing slowly<br> over time.A.False<br> B.true<br> Previous

oksian1 [2.3K]

Answer:

true

Explanation:

7 0

3 years ago

What conducts better, metal or nometal? <br> why?

Rama09 [41]

Metal because it’s more stronger

8 0

2 years ago

Which of these half-reactions represents reduction?

gogolik [260]

Answer: The half-reactions represents reduction are as follows.

$Cr_{2}O^{2-}_{7} \rightarrow Cr^{3+}$
$MnO^{-}_{4} \rightarrow Mn^{2+}$

Explanation:

A half-reaction where addition of electrons take place or a reaction where decrease in oxidation state of an element takes place is called reduction-half reaction.

For example, the oxidation state of Cr in $Cr_{2}O^{2-}_{7}$ is +6 which is getting converted into +3, that is, decrease in oxidation state is taking place as follows.

$Cr_{2}O^{2-}_{7} + 3 e^{-} \rightarrow Cr^{3+}$

Similarly, oxidation state of Mn in $MnO^{-}_{4}$ is +7 which is getting converted into +2, that is, decrease in oxidation state is taking place as follows.

$MnO^{2-}_{4} + 5 e^{-} \rightarrow Mn^{2+}$

Thus, we can conclude that half-reactions represents reduction are as follows.

$Cr_{2}O^{2-}_{7} \rightarrow Cr^{3+}$
$MnO^{-}_{4} \rightarrow Mn^{2+}$

3 0

2 years ago