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Nitella [24]
4 years ago
10

Does it require more force to stop a bus or a bike moving at the same speed

Chemistry
1 answer:
iVinArrow [24]4 years ago
7 0
Well depends how fast they're going if it's a slow speed a bus but at a fast speed a bike because you wanna be careful while stopping
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The simplest particles of iron are
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The simplest particles are atoms.
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4 years ago
A chemist wishes to perform the following reaction: N2 + 3 H2 → 2 NH3 If only 14.0 g of N2 is available, what is the minimum amo
djyliett [7]

Answer:

3 grams

Explanation:

14 g of N2   is 1/2 mole

  If you halve the N2   in the balanced equation , you have to halve the H2 down to 1.5 moles of H2    which is 3 grams

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2 years ago
How many grams of a nonelectrolyte (78.2 g/mol) must be dissolved in 1 kg of solvent to obtain a freezing point of solution of 1
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Answer Tu mama por si acaso

Explanation:

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3 years ago
Suppose you want to use a combustion chemical reaction to cook hot dogs and hamburgers. what type of reaction would you want? a
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Answer : The correct answer is a) an exothermic reaction that releases energy.

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Since it says hot dogs and hamburgers are cooked means they are undergoing combustion chemical reaction and so they are exothermic reactions. So option a) an exothermic reaction which releases energy is correct .

6 0
3 years ago
Read 2 more answers
Calculate the volume in liters of a potassium iodide solution that contains of potassium iodide . Be sure your answer has the co
Anna11 [10]

Answer:

23.8 L

Explanation:

There is some info missing. I think this is the original question.

<em>Calculate the volume in liters of a 0.0380M potassium iodide solution that contains 150 g of potassium iodide. Be sure your answer has the correct number of significant digits.</em>

<em />

The molar mass of potassium iodide is 166.00 g/mol. The moles corresponding to 150 grams are:

150 g × (1 mol/166.00 g) = 0.904 mol

0.904 moles of potassium iodide are contained in an unknown volume of a 0.0380 mol/L potassium iodide solution. The volume is:

0.904 mol × (1 L/0.0380 mol) = 23.8 L

6 0
3 years ago
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