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timama [110]
3 years ago
14

Astrology, a belief in a relationship between constellations of stars and life events,

Chemistry
1 answer:
yanalaym [24]3 years ago
3 0

Answer:

Pseudoscience

Explanation:

"Astrology has not demonstrated its effectiveness in controlled studies and has no scientific validity, thus regarded as pseudoscience."

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An atom of lithium (Li) forms an ionic bond with an atom of chlorine (Cl) to form lithium chloride. How are the valence electron
miskamm [114]

Answer: Option (D) is the correct answer.

Explanation:

Atomic number of lithium is 3 and electrons in its shell are distributed as 2, 1. Atomic number of chlorine is 17 and electrons in its shell are distributed as 2, 8, 7.

Thus, we can see that lithium has 1 extra electron and chlorine has deficiency of 1 electron. Therefore, in order to gain stability lithium will transfer its 1 extra electron to chlorine atom.

Thus, we can conclude that electrons are transferred from the lithium atom to the chlorine atom.

6 0
3 years ago
Read 2 more answers
What is the equilibrium constant, KC if the reaction is a gas phase reaction? (Ans.: Gas: KC = 0.328 dm3/mol)
valentina_108 [34]

Answer:

Equilibrium constant Kc = Qc = quotient of reactant(s) and product(s)

Kc = [C]x[D]y..../[A]m[B]n..... = 0.328dm3/mol, where [C]x[D]y is the product and [A]m[B]n is the reactant(Both in gaseous states)

Explanation:

When a mixture of reactants and products of a reaction reaches equilibrium at a given temperature, its reaction quotient always has the same value. This value is called the equilibrium constant (K) of the reaction at that temperature. As for the reaction quotient, when evaluated in terms of concentrations, it is noted as Kc.

That a reaction quotient always assumes the same value at equilibrium can be expressed as:

Qc (at equilibrium) = Kc =[C]x[D]y…/[A]m[B]n…

This equation is a mathematical statement of the law of mass action: When a reaction has attained equilibrium at a given temperature, the reaction quotient for the reaction always has the same value.

6 0
2 years ago
Draw one line connecting each factor that increases the rate of a
VLD [36.1K]

Answer:

Adding a catalyst - More collisions every second and more collisions with enough energy to break bonds.

Increase in pressure - more collisions every second

Increase in temperature - more collisions every second with enough energy to break bonds

Explanation:

According to the collision theory, chemical reaction occurs as a result of collision between reacting particles. Only particles that possess energy above the activation energy of the reaction can collide and result in product formation. Collision of particles having energy less than the activation energy merely result in elastic collisions.

Adding a catalyst lowers the activation energy of the reaction. If the activation energy is lowered, more reactants collide and more of those collisions now have enough energy to break bonds.

When the temperature is increased, the particles become more energetic hence more collisions with energy to break bonds occur.

Increase in pressure brings the reactant particles into close proximity hence more collisions occur.

4 0
2 years ago
A reaction between 46 grams of sodium and 71 grams of chlorine formed table salt and heat.
vazorg [7]

Answer:

d. 117 grams

Explanation:

The mass of the table salt produced will be 117 grams.

Chemical reactions obey the law of conservation of mass. In this regard, matter is neither created nor destroyed in the course of a chemical reaction. It is expected that the mass of the reactants and products remain the same.

 The reaction expression:

         2Na + Cl₂  →   2NaCl

So, mass of sodium  = 46g

      mass of chlorine formed = 71g

Mass of NaCl  = 46 + 71 = 117g

7 0
3 years ago
For the balanced equation shown below, if the reaction of 0.112 grams of
Alekssandra [29.7K]

Answer:

The answer is 74.5%.

Explanation:

As we know that % yield=  \frac{actual yield}{theoretical yield} x 100%.

Therefore,

Step 1 Calculate Theoretical yield:

0.112H_{2} x   \frac{1 mol H_{2} }{2.016 g of H{2} }    x    \frac{4 mol H_{2}O }{4 mol H_{2} }    x  \frac{18.02 g H_{2}O }{1 mol H_{2}O}   = 1.001 g H_{2}O

Now Step 2

% yield   =  \frac{actual yield}{theoretical yield} x 100% =   \frac{0.745g}{1.001g} = 74.5%

8 0
3 years ago
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