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3 years ago

Astrology, a belief in a relationship between constellations of stars and life events,

Chemistry

1 answer:

yanalaym [24]3 years ago

3 0

Answer:

Pseudoscience

Explanation:

"Astrology has not demonstrated its effectiveness in controlled studies and has no scientific validity, thus regarded as pseudoscience."

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Calculate the number of ATPs generated by the complete metabolic oxidation of tripalmitin (tripalmitoylglycerol). Hydrolysis of

trapecia [35]

Answer:

Explanation:

412 ATP's will be generated from the complete metabolic oxidation of tripalmitin (tripalmitoylglycerol)

130 ATP from the oxidation of palmitate

22 ATP from the oxidation of glycerol

Altogether 130 + 22 = 412 ATP will be produced.

Here in case of tripalmitin (tripalmitoylglycerol), we have 51 carbons.

When 51 carbons can produce 412 ATPs

Then 1 carbon will produce how many ATPs = 412 ATPs/ 51 carbon= 8.1 ATPs.

This shows that ATP yield per carbon often oxidized will be 8.1 ATPs

Now we will see the ATP yield in the case of glucose.

Glucose is made up of 6 carbon and complete oxidation of glucose will produce 38 ATPs

When 6 carbons can yield 38 ATPs

Then 1 carbon can yield how many ATPs= 38 ATPs/ 6 carbons= 6.33 ATPs.

So, ATP yield per carbon in case of glucose will be 6.33 ATPs

8 0

3 years ago

Validate how valence electrons determine the chemical reactivity of an element: give 2 examples of elements with high reactivity

Ostrovityanka [42]

Nitrogen is more reactive than oxygen and oxygen than chlorine

8 0

3 years ago

How many non bonded electron pairs are in the tetracyanoethylene molecule?

algol [13]

Each of the Nitrogen atoms has 2 non bonded valence electrons, meaning that there are 4 pairs total.

8 0

3 years ago

Read 2 more answers

How many moles are in NaOH?

CaHeK987 [17]

1 mole consist of 6.022 ×10 ²³

Therefore in NaOH = 6.022 ×10 ²³ moles of NaOH

6 0

3 years ago

Read 2 more answers

State what would be observed when the following pairs of reagents are mixed in a test tube.

Mandarinka [93]

Answer:

(i). C6H2COOH and Na2CO3(aq)

observation: Bubbles of a colourless gas (carbon dioxide gas)

(ii) CH3CH2CH2OH and KMnO4 /H

observation: The orange solution turns green.

[This is because oxidation of propanol to propanoic acid occurs]

(iii) CH3CH2OH and CH3COOH + conc. H2SO4

observation: A sweet fruity smell is formed.

[This is because an ester, diethylether is formed]

(iv) CH3CH = CHCH3 and Br2 /H2O

observation: a brown solution is formed.

4 0

3 years ago