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Gre4nikov [31]
3 years ago
8

If you have a pitcher of lemonade and the recipe calls for 2 lemons and you decided to use 4, would this be considered diluted o

r concentrated
Chemistry
1 answer:
pantera1 [17]3 years ago
7 0

Answer: This would be considered concentrated because if you're upping the recipe on your own accord, it would be way more sour, causing the lemonade to be more concentrated. It would be diluted if you added less than 2 lemons.

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Gallium is a metallic element in Group III. It has similar properties to aluminium.
Liula [17]

Answer:

Gallium has Orthorhombic and forms ionic bonds with metals

Explanation:

The structure of gallium is Orthorhombic and it has a high neutron capture cross section. It is very stable in dry air but oxidizes in moist air. It reacts with oxygen to form Ga2O3. It has a valence of III. Its electronic configuration is  

Ar 3d10 4s2 4p1

It is found in the 3A group of periodic table and it mostly forms ionic bonds with metal.  

3 0
3 years ago
Susan needs to simplify the expression shown below what should be her first step
Digiron [165]
Susan should follow PEMDAS,

Parentheses
Exponents
Multiplication
Division
Addition
Subtraction,

So, the first step should be, to solve the equation in the parentheses.

I hope this helps!
5 0
3 years ago
In the late 1400s,ties among people of the same formed the basics of most aspects of life in rural west Africa
lara31 [8.8K]
Can u write it more specifically? so that I can answer
6 0
3 years ago
How many grams of water will be produced from 50 g hydrogen reacting with 50 g oxygen?
DanielleElmas [232]

We need to first come up with a balanced equation:


4H+O_{2} → 2H_{2}O


We know that the molar ratio of hydrogen to oxygen to water now is 4:1:2.


Converting the amount of grams given to moles is as follows:


Hydrogen: \frac{1mole}{1.008g}*50g=49.6mol


Oxygen: \frac{1mole}{15.999g}*50g=3.125mol


We know now that the limiting reactant is oxygen. We can then know that the number of moles of water are produced are double the number of moles of oxygen used due to the ratio that we established at the beginning - 4:1:2.


So we now can use 6.25 moles of water as the amount produced.


Then we convert moles of water to grams:


\frac{18.015g}{1mole} *6.25mol=112.59g


Now we know that there are 112.59g of water produced when we start with 50g of hydrogen and 50g of water.

4 0
3 years ago
QUESTION 10
worty [1.4K]
I have no idea honestly I don’t remember I had it and I forgot it
6 0
3 years ago
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