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Gre4nikov [31]
3 years ago
8

If you have a pitcher of lemonade and the recipe calls for 2 lemons and you decided to use 4, would this be considered diluted o

r concentrated
Chemistry
1 answer:
pantera1 [17]3 years ago
7 0

Answer: This would be considered concentrated because if you're upping the recipe on your own accord, it would be way more sour, causing the lemonade to be more concentrated. It would be diluted if you added less than 2 lemons.

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How many molecules of oxygen are needed to make 3.5 oxygens of water?​
max2010maxim [7]

Answer:

57.6g

Explanation:

So, if in one mole of water, 16 g of oxygen atom is present. Then, in 3.6 moles of water, the mass of oxygen present will be 3.6×16=57.6g. Therefore, the amount of oxygen present in 3.6 g water is option (B)- 57.6 g.

8 0
2 years ago
3. You are asked to prepare an aqueous solution. What would be a better choice for a solute potassium nitrate or
liubo4ka [24]

Answer:

i do not knowwww

Explanation:

8 0
3 years ago
What is the mass of substance that exactly fills a 247.2 mL container? The density of the substance is 0.81 g/mL. Give the answe
matrenka [14]

Answer:

<h2>mass = 200.23 g</h2>

Explanation:

The density of a substance can be found by using the formula

Density =  \frac{mass}{volume}

Since we are finding the mass

<h3>mass = Density × volume</h3>

From the question

Density = 0.81 g/mL

volume = 247.2 mL

Substitute the values into the above formula and solve for the mass

mass = 0.81 × 247.2

= 200.232

We have the final answer as

<h3>mass = 200.23 g to 2 decimal places</h3>

Hope this helps you

3 0
3 years ago
Which compound is an Arrhenius base?
Dmitry_Shevchenko [17]
I was hoping that some choices would be given to choose from. As there are no choices given, so i am answering the question based on my knowledge and hope that it comes to your help. Calcium hydroxide is a good example of Arrhenius base. An Arrhenius base is actually a substance that releases a hydroxyl ion in water.
3 0
3 years ago
If we start with 8000 atoms of radium-226 how much would remain after 3200 years?
olya-2409 [2.1K]
<h3>Answer:</h3>

2000 atoms

<h3>Explanation:</h3>

We are given the following;

Initial number of atoms of radium-226 as 8000 atoms

Time taken for the decay 3200 years

We are required to determine the number of atoms that will remain after 3200 years.

We need to know the half life of Radium

  • Half life is the time taken by a radio active material to decay by half of its initial amount.
  • Half life of Radium-226 is 1600 years
  • Therefore, using the formula;

Remaining amount = Original amount × 0.5^n

where n is the number of half lives

n = 3200 years ÷ 1600 years

 = 2

Therefore;

Remaining amount = 8000 atoms × 0.5^2

                                = 8000 × 0.25

                                 = 2000 atoms

Thus, the number of radium-226 that will remain after 3200 years is 2000 atoms.

6 0
3 years ago
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