Answer:
Option C
Explanation:
Given:
- Clock speed f = 33 MHz
- The width of the bus w = 32 bits
Find:
what is the theoretical throughput in MiBytes?
Solution:
- First step is to convert the width of the bus to bytes as follows:
Bytes = 32 bits * (1 Bytes / 8 bits)
Bytes = 32 / 8
- Second step is to evaluate the time of the cycle:
Time period of clock T = 1 / f
Time period of clock T = 1 s / (33*10^6)
T = (1 / 33*10^6)
- Third step is to formulate the number of byte:
Number of byte = Bytes * T
= (32 / 8*33*10^6)
- Fourth step is to convert to Mi bytes:
Mibytes = Number of byte / 2^20
Mibytes = (32 / 8*33*10^6 * 2^20)
- The correct option is C
They are pushing on opposite sides against each other. The cart is moving forwards
Answer:
Option (B) is correct.
Explanation:
Given that the molecules of hydrogen gas () react with molecules of oxygen gas () in a sealed reaction chamber to produce water ().
The governing equation for the reaction is
From the given, the only fact that can be observed that 2 moles of and 1 mole of reacts to produce 2 moles of .
As the mass of 1 mole of grams ... (i)
The mass of 1 mole of grams ...(ii)
The mass of 1 mole of grams (iii)
Now, the mass of the reactant = Mass of 2 moles of + mass 1 mole of
[ using equations (i) and (ii)]
grams.
Mass of the product = Mass of 2 moles of
[ using equations (iii)]
=36 grams
As the mass of reactants = mass of the product.
So, mass is conserved.
Hence, option (B) is correct.
An array of this size can produce an average of 350-850 kWh of AC energy per month.
Solar technologies convert sunlight into electrical energy either through photovoltaic (PV) panels or through mirrors that concentrate solar radiation. This energy can be used to generate electricity or be stored in batteries or thermal storage.
Solar panel systems are measured in terms of kW. A common size solar panel array is usually around 5kW. An array of this size can produce an average of 350-850 kWh of AC energy per month.
learn more about Solar panel
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Explanation:
average speed = total distance travelled / total time travelled
time to travel the first 6km: 6 / 50 = 3/25 (h)
time to travel the next 6km: 6 / 90 = 1/15 (h)
[I think there's problem in the question 'cause 900km/h sounds impossible for normal person to travel in normal condition]
The total time: 3/25 + 1/15 = 14/75 (h)
Average speed over the 12 km drive will be: