Answer:
Option C
Explanation:
Given:
- Clock speed f = 33 MHz
- The width of the bus w = 32 bits
Find:
what is the theoretical throughput in MiBytes?
Solution:
- First step is to convert the width of the bus to bytes as follows:
Bytes = 32 bits * (1 Bytes / 8 bits)
Bytes = 32 / 8
- Second step is to evaluate the time of the cycle:
Time period of clock T = 1 / f
Time period of clock T = 1 s / (33*10^6)
T = (1 / 33*10^6)
- Third step is to formulate the number of byte:
Number of byte = Bytes * T
= (32 / 8*33*10^6)
- Fourth step is to convert to Mi bytes:
Mibytes = Number of byte / 2^20
Mibytes = (32 / 8*33*10^6 * 2^20)
- The correct option is C
