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jasenka [17]
3 years ago
5

In a chemical reaction, molecules of hydrogen gas (H2) react with molecules of oxygen gas (O2) in a sealed reaction chamber to p

roduce water (H2O). This occurs through the following chemical equation. 2H2 + O2 → 2H2O What is conserved as the reaction occurs in the reaction chamber? A. temperature B. mass C. flammability D. molecule size
Physics
1 answer:
11Alexandr11 [23.1K]3 years ago
8 0

Answer:

Option (B) is correct.

Explanation:

Given that the molecules of hydrogen gas (H_2) react with molecules of oxygen gas (O_2) in a sealed reaction chamber to produce water (H_2O).

The governing equation for the reaction is

2H_2 +O_2 \rightarrow 2H_2O

From the given, the only fact that can be observed that 2 moles of H_2 and 1 mole of O_2 reacts to produce 2 moles of H_2O.

As the mass of 1 mole of H_2 = 2 grams ... (i)

The mass of 1 mole of O_2 = 32 grams ...(ii)

The mass of 1 mole of H_2O = 18 grams (iii)

Now, the mass of the reactant = Mass of 2 moles of H_2 + mass 1 mole of  O_2

= 2 \times 2 + 32  [ using equations (i) and (ii)]

=4+32 = 36 grams.

Mass of the product = Mass of 2 moles of H_2O

=2\times 18 [ using equations (iii)]

=36 grams

As the mass of reactants = mass of the product.

So, mass is conserved.

Hence, option (B) is correct.

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Determine a formula for the magnitude of the force F exerted on the large block (Mc) so that the mass Ma does not move relative
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Answer:

The magnitude of the force F is given by

F =  (M_{a} + M_{b} + M_{c} ) *(M_{b}*g/(\sqrt{M_{a} ^{2}-M_{b} ^{2}}))

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(M_{a} ^{2}  -  M_{b} ^{2}) * a^{2} = M_{b} ^{2} *g^{2}

a^{2} = M_{b} ^{2} *g^{2}/(M_{a} ^{2}  -  M_{b} ^{2})

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a = M_{b}*g/(\sqrt{M_{a} ^{2}-M_{b} ^{2}})

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F =  (M_{a} + M_{b} + M_{c} ) *(M_{b}*g/(\sqrt{M_{a} ^{2}-M_{b} ^{2}}))

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