This Question has mistakes.Correct question is
An undamped oscillator has period τo=1.000s
, but I now add a little damping so that its period changes to τ1=1.001s.
What is the damping factor β? By what factor will the amplitude of oscillation decrease after 10 cycles? Which effect of damping would be more noticeable, the change of period or the decrease of the amplitude?
Answer:
β=0.28 /sec
Amplitude=0.0606
Explanation:
The rust is the product and evidence
Answer:
a) Height of the antenna (in m) for a radio station broadcasting at 604 kHz = 124.17 m
b)Height of the antenna (in m) for radio stations broadcasting at 1,710 kHz =43.86 m
Explanation:
(a) Radiowave wavelength= λ = c/f
As we know, Radiowave speed in the air = c = 3 x 10^8 m/s
f = frequency = 604 kHz = 604 x 10^3 Hz
Hence, wavelength = (3x10^8/604x10^3) m
λ
= 496.69 m
So the height of the antenna BROADCASTING AT 604 kHz = λ /4 = (496.69/4) m
= 124.17 m
(b) As we know , f = 1710 kHz = 1710 x 10^3 Hz (1kHZ = 1000 Hz)
Hence, wavelength = λ = (3 x 10^8/1710 x 10^3) m
λ= 175.44 m
So, height of the antenna = λ /4 = (175.44/4) m
= 43.86 m
Answer:
1 . rays should passs through correct center or points(i.e. optic center or focus)
2.your line representing rays should be straight and u should tell the nature of image
Explanation:
Answer:
7.8
Explanation:
Here, an effort of 50 N is applied at the car key and overcomes the resistance(or load) of 390 N at the lid.
mechanical advantage
=load/effort
=390 N/50 N
=7.8
