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VikaD [51]
3 years ago
6

The hypotenuse of a right triangle is 10 inches long. One of the legs is 2 inches longer than the other one. If x is the length

of the shorter leg, what is the equation
Mathematics
1 answer:
iVinArrow [24]3 years ago
5 0

Answer:

The equation is

X²+2x-48 = 0

Shorter one is 6 inches

Other side= 8 inches

Step-by-step explanation:

The equation for a right angle triangle normally is

A² = B² + C²

Where A = hypotenuse

Then B and C are the order sides of the triangle.

This time

Hypotenuse= 10 inches

The shorter one is X

While the other one is X+2

The equation

10²= x² +(x+2)²

100= x² + x² + 4x +4

100 - 4 = 2x² +4x

96= 2x² +4x

48 = x² +2x

X²+2x-48 = 0

Solving for x

X² +8x-6x-48= 0

X(x+8)-6(x+8)=0

(X-6)(x+8)= 0

X= 6 or x= -8

Definitely x is posiy

So x= 6

Shorter one is 6 inches

Other side= 6+2= 8 inches

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Which expression represents the distance between the points (11, 4) and (5,8)?
antiseptic1488 [7]

Answer:

\displaystyle d = 2\sqrt{13}

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<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

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  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
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  1. Substitute in points [Distance Formula]:                                                       \displaystyle d = \sqrt{(5-11)^2+(8-4)^2}
  2. [√Radical] (Parenthesis) Subtract:                                                                 \displaystyle d = \sqrt{(-6)^2+(4)^2}
  3. [√Radical] Evaluate exponents:                                                                    \displaystyle d = \sqrt{36+16}
  4. [√Radical] Add:                                                                                               \displaystyle d = \sqrt{52}
  5. [√Radical] Simplify:                                                                                         \displaystyle d = 2\sqrt{13}
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3 years ago
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