The hypotenuse of a right triangle is 10 inches long. One of the legs is 2 inches longer than the other one. If x is the length
of the shorter leg, what is the equation
1 answer:
Answer:
The equation is
X²+2x-48 = 0
Shorter one is 6 inches
Other side= 8 inches
Step-by-step explanation:
The equation for a right angle triangle normally is
A² = B² + C²
Where A = hypotenuse
Then B and C are the order sides of the triangle.
This time
Hypotenuse= 10 inches
The shorter one is X
While the other one is X+2
The equation
10²= x² +(x+2)²
100= x² + x² + 4x +4
100 - 4 = 2x² +4x
96= 2x² +4x
48 = x² +2x
X²+2x-48 = 0
Solving for x
X² +8x-6x-48= 0
X(x+8)-6(x+8)=0
(X-6)(x+8)= 0
X= 6 or x= -8
Definitely x is posiy
So x= 6
Shorter one is 6 inches
Other side= 6+2= 8 inches
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