Answer:
for the cellular respiration the human body needs 1.424 E21 molecules of glucose
Explanation:
mass glucose = 24 g
∴ Mw glucose = 180.156 g/mol
∴ 1 mol ≡ 6.022 E23 molecules
⇒ mol glucose = (24 g)×(mol/180.156 g) = 0.1332 mol glucose
⇒ molecules glucose = (0.1332 mol glucose)×(6.022 E23 molecules/mol)
⇒ molecules glucose = 1.424 E21 molecules
Unit cells.
They are the smallest group of atoms that take form of a crystal and can repeat in 3 dimensions.
The reduction of alkyne to an alkene in the first step allows the best reagent to be chosen for each subsequent step.
Describe reagents.
A reagent is merely an essential component of a chemical reaction, it should be mentioned. It is an ingredient that speeds up the reaction.
With H2 and Lindlar's catalyst, an alkyne is reduced to alkene as the initial step in this process. Alkene will then be brominated to produce allyl bromide as the next step.
In this instance, the required allyl alcohol will be produced via the reaction of allyl bromide with NaOH.
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