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andrew-mc [135]
3 years ago
15

The handbook density of gold is 19.3

Chemistry
1 answer:
Soloha48 [4]3 years ago
3 0

Answer:

Percent error = -4.7%

Explanation:

Given data:

Actual density value = 19.3 g/cm³

Measured value of density by student = 18.4 g/cm³

Percent error = ?

Solution:

Formula:

Percent error = ( measured value - actual value / actual value ) × 100

Now we will put the values.

Percent error = ( 18.4 g/cm³ - 19.3 g/cm³ /  19.3 g/cm³) × 100

Percent error = (-0.9 g/cm³ /  19.3 g/cm³) × 100

Percent error = -0.047  × 100

Percent error = -4.7%

Negative sign shows that measured value is less than actual value.

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If 125 g of CaCO3 is mixed and reacted with 125 g of HCl, which reactant is limiting and how many grams of CO2 can be made?
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Answer:

CaCO3 is the limiting reactant

55 g of CO2 is made

Explanation:

First we must put down the reaction equation;

CaCO3(s) + 2HCl(aq) ---------> CaCl2(s) + H2O(l) + CO2(g)

Number of mole of CaCO3 = 125g/100gmol-1 = 1.25 moles

From the reaction equation;

1 mole of CaCO3 yields 1 mole of CO2

Hence 1.25 moles of CaCO3 yields 1.25 moles of CO2

For HCl;

number of moles of HCl = 125g/36.5 g mol-1 = 3.42 moles

From the reaction equation;

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Hence CaCO3 is the limiting reactant.

Mass of CO2 produced = 1.25g * 44 gmol-1 = 55 g of CO2

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3 years ago
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Answer:

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Explanation:

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make given mass become the subject of the formula by

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