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valentinak56 [21]
2 years ago
10

Predict how the surface of a sand dune would change if a river began flowing through the area over the course of 10,000 years. W

rite your explanation in the space
below.
​
Chemistry
1 answer:
dedylja [7]2 years ago
8 0

Answer:

the sand dune would become flattened and eventually turn into sedementary rock

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Which type of force does a magnet use to move a nail?
galben [10]

Answer:

C maybe

Explanation:

3 0
2 years ago
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How many moles are in 5.0 x 1025 atoms of iron
Mnenie [13.5K]
1 mole --------------- 6.02 x 10²³ atoms
( moles iron) -------- 5.0 x 10²⁵ atoms

( moles iron ) = 5.0 x 10²⁵ x 1 / 6.02 x 10²³

moles iron = 5.0 x 10²⁵ / 6.02 x 10²³

= 83.05 moles of iron

hope this helps!
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3 years ago
The lithospheric plates float on top of the _______, which is a weak part of the mantle that flows slowly.
alexandr1967 [171]
<span>The lithospheric plates float on top of the _______, which is a weak part of the mantle that flows slowly.
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asthenosphere
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Which of the following type of radiation is represented by 0 over negative 1 e? A.alpha emission B.beta emission C.positron emis
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7 0
3 years ago
a compound has 15.39 g of gold for every 2.77 g of chlorine. simplified there is _____ g of gold for every 1 g of chlorine
iren [92.7K]

Answer:

There is 5.56 g of gold for every 1 g of chlorine

Explanation:

The ratio is the relationship between two numbers, defined as the ratio of one number to the other. So, the ratio between two numbers a and b is the fraction \frac{a}{b}

You know that a compound has 15.39 g of gold for every 2.77 g of chlorine. This can be expressed by the ratio:

\frac{15.39 g  of gold}{2.77 g of chlorine}

The proportion is the equal relationship that exists between two reasons and is represented by:    \frac{a}{b}=\frac{c}{d}

This reads a is a b as c is a d.

To calculate the amount of gold per 1 g of chlorine, the following proportion is expressed:

\frac{15.39 g  of gold}{2.77 g of chlorine}=\frac{mass of gold}{1 g of chlorine}

Solving for the mass of gold gives:

mass of gold=1 g of chlorine*\frac{15.39 g  of gold}{2.77 g of chlorine}

mass of gold= 5.56 grams

So, <u><em>there is 5.56 g of gold for every 1 g of chlorine</em></u>

5 0
3 years ago
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