Hello:
let : f(x) = <span>x3 − 6x2 + kx + 10
</span><span>If (x + 2) is a factor of x3 − 6x2 + kx + 10 : f(-2) = 0
(-2)^3-6(-2)² +k(-2)+10=0
-8 -24-2k +10 = 0
-2k =8+24-10
-2k = 22
k = -11</span>
There are 52 weeks in a year. 1 frog per week: 52 * 1 = 52
So, cloning about 1 frog per week would be reasonable.
The answer: Time= Distance divide Speed.
Speed= 675,000 divide 900= 750 minutes. Convert that to hours and that leaves you with 12 hours and a half. If these questions are bothering you, just revise them- they’re speed distance time equations and i’d be blessed if they come up in my maths exam tomorrow.
Answer:
Step-by-step explanation:
B, y=5x
Answer:
Her speed on the summit was 35 mph.
Step-by-step explanation:
Her speed on the summit was "x" mph while her speed while climbing was "x - 10" mph. The distance she rode uphill was 55 miles and on the summit it was 28 miles. The total time she explored the mountain was 3 hours. Therefore:
time uphill = distance uphill / speed uphill = 55 / (x - 10)
time summit = distance summit / speed summit = 28 / x
total time = time uphill + time summit
3 = [55 / (x - 10)] + 28 / x
3 = [55*x + 28*(x - 10)]/[x*(x - 10)]
3*x*(x - 10) = 55*x + 28*x - 280
3x² - 30*x = 83*x - 280
3x² - 113*x + 280 = 0
x1 = {-(-113) + sqrt[(-113)² - 4*(3)*(280)]}/(2*3) = 35 mph
x2 = {-(-113) - sqrt[(-113)² - 4*(3)*(280)]}/(2*3) = 2.67 mph
Since her speed on the uphill couldn't be negative the speed on the summit can only be 35 mph.
