Question

A hungry college student just finished eating a large cheese and pepperoni pizza from​ Doug's Pizza Palace and felt there​ wasn't enough cheese and pepperoni on it. This led him to wonder what the average weight of a large cheese and pepperoni pizza was at​ Doug's Pizza Palace. Doug ordered a large cheese and pepperoni pizza from​ Doug's Pizza Palace on 15 randomly selected days during a particular term and weighed each before eating it. Suppose all conditions are met for inference using the​ one-sample t-methods. The student obtained the following​ 95% confidence interval​ (in grams) for the population​ mean, (862,1028). What is the margin of​ error?

Answer 1

Answer: 83

Step-by-step explanation:

The confidence interval for population mean is given by :-

$\overline{x}\pm E$

Given : The student obtained the following​ 95% confidence interval​ (in grams) for the population​ mean, (862,1028).

Here,

Lower limit of the confidence interval : $\overline{x}-E=862$  (1)

Upper limit of the confidence interval : $\overline{x}+E=1028$   (2)

Subtracting (1) from (2) , we get

$2E=166\\\\\Rightarrow\ E=\dfrac{166}{2}=83$

Hence, the margin of​ error = 83