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ZanzabumX [31]
3 years ago
12

Please answer quickly

Physics
2 answers:
andreyandreev [35.5K]3 years ago
8 0

Explanation:

I think the third container is in correct

malfutka [58]3 years ago
3 0
Did you get ???? Tell me if you did
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If you throw your annoying little sister down the stairs with a force of 60 N and she weighs 30 kg. What’s her acceleration rate
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Her acceleration rate is death.

Explanation:

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How do you make the chemical equations LiOH+H2(SO4) and H2O+Li2(SO4) balanced?
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3 years ago
a stone is thrown vertically upwards with a velocity of 20 m per second determine the total time of flight of stone in air​
miv72 [106K]

Answer:

Explanation:

The best way to do this is to remember the rule about the halfway mark in a parabolic path. At a trajectory's half way point in its travels, it will be at its max height. To get the total time in the air, we take that time at half way and double it. Here's what we know that we are told:

initial velocity is 20 m/s

Here's what we know that we are NOT told:

a = -9.8 m/s/s and

final velocity is 0 at an object's max height in parabolic motion.

We will use the equation:

v=v_0+at where v is final velocity and v0 is initial velocity. Filling in:

0 = 20 + (-9.8)t and

-20 = -9.8t so

t = 2 seconds. The stone reaches its max height 2 seconds after it is thrown; that means that after another 2 seconds it will be on the ground. Total air time is 4 seconds.

8 0
3 years ago
In the picture above, what is the period of the pendulum?<br> (Remember to include a unit)
-BARSIC- [3]
69 i agree with her hope this helps
6 0
3 years ago
Mario golpea el balón con el pie para lanzárselo a Tamara que está situada a 18 m de distancia. El ángulo de salida del balón es
Brilliant_brown [7]

Answer:

y = 0.99 m

Explanation:

This is a projectile launching exercise, let's start by finding the components of the initial velocity, using trigonometry

         cos θ = v₀ₓ / v₀

         sin θ = v_{oy} / v₀

         v₀ₓ = vo cos θ

         v_{oy} = I go sin θ

         v₀ₓ = 15 cos 30 = 12.99 m / s

         v_{oy} = 15 sin 30 = 7.5 m / s

Let's find the time it takes to travel x = 18 m

         x = v₀ₓ t

         t = x / v₀ₓ

         t = 18 / 12.99

         t = 1,385 s

at this point it is at a height of

         y = v_{oy} - ½ g t²

         y = 7.5 1.385 - ½ 9.8 1.385²

         y = 0.99 m

therefore the camera must place the foot 99 cm from the ground

7 0
3 years ago
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