The reflection transformation in the question is a rigid transformation,
therefore, the image and the preimage are congruent.
The statements that are true are;
Reasons:
The given parameter are;
Triangle ΔABC is reflected across the line 2·X, to map onto triangle ΔRST
Required:
To select the true statements
Solution:
A reflection is a rigid transformation, therefore, the distance between corresponding points on the image and the preimage are equal.
Therefore;
AB = RS
BC = ST
AC = RT
Given that the image formed by a reflection is congruent to the preimage, we have;
ΔABC ≅ ΔRST
∠ABC ≅ ∠RST
m∠ABC = m∠RST by the definition of congruency
∠BCA ≅ ∠STR
m∠BCA = m∠STR by the definition of congruency
∠BAC ≅ ∠SRT
m∠BAC = m∠SRT by the definition of congruency
Therefore, the true statements are;
- <u>AB = RS</u>; Image formed by rigid transformation
- <u>∠ABC ~ ∠RST</u>; Definition of similarity
- <u>ΔABC = ΔRST</u>; By definition of congruency
- <u>m∠BAC = m∠SRT</u>; by the definition of congruency
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Answer: Infinitely Many Solutions
Step-by-step explanation is below.
The answer will be
15m+10
Answer:
∠ D = 28°
Step-by-step explanation:
The external angle of a triangle is equal to the sum of the 2 opposite interior angles.
∠ EBC is an exterior angle of Δ ABE, thus
∠ EBC = 90° + 34° = 124°
BD bisects ∠ EBC, so
∠ EBD = 124° ÷ 2 = 62° , then
∠ D = 180° - (90 + 62)° = 180° - 152° = 28° ( angle sum of triangle )