Hey there!
2 moles will be produced.
In N₂ there are 2 nitrogen atoms. In NH₃ there is 1 nitrogen atom.
So, there will be twice as many moles produced because there will be twice as many molecules.
Hope this helps!
Answer: mercury
Explanation: I looked up the answer to your question.
To solve this problem,
we must first examine the chemical formula of an alkene (CnH2n) and notice that
there are 2 H atoms for every 1 C atom.
<span>
Therefore this means that we can calculate the
weight percent of Hydrogen (H) using the molecular formula: </span>
<span>wt% H2 = 2n * (1.0g/mol H)/[2n*(1.0g/mol H) + n*(12.0g/mol
C)) x 100 = 14.3 wt% H
So for any alkene with mass of 0.561g, this contains
(0.143)x(0.561g) = 0.080 g H
Now, we calculate the number of moles of H this is by
dividing with the molar mass:
moles H = (0.080g H) / (1.00 g/mol H) = 0.08 moles H.
We know that there are 0.5 moles of water per mole of hydrogen,
therefore the moles of H2O formed is:
moles H2O = 0.5 * moles H = 0.5 * (0.08) = 0.04 moles H2O</span>
Answer:
<span>0.04 moles water</span>
Answer:
Vol concentrated HCl needed = 1.73 ml
Explanation:
Prep 550 ml of HCl(aq) solution with pH = 1.60 at 25°C using 8M stock concentrate.
[HCl] = [H⁺] = 10⁻¹°⁶⁰M = 0.0251M HCl(aq)
Molarity Concentrate x Volume Concentrate = Molarity Dilute x Volume Dilute
8M x Vol Conc. = 0.0251M x 550ml
Vol Conc needed = 0.0251M x 550 ml / 8M = 1.73 ml of concentrate
Mixing => to the quantity of water in the mixing flask transfer 1.73 ml of the 8M HCl concentrate solution and dilute up to but not to exceed the calibration mark on the mixing flask.
Hey there!
1.Hydrogen
2.<span>PbO₂=Pb+O₂
Hope this helps!</span>