For the first part, use the question M=mol/vol (liters)
To do this, you have the given 1.6 M solution
divide the 360g by the molar mass of ethanol (44.07) to get moles
360/44.07=8.16 mol
so
1.6M = 8.16 mol/x vol
volume: 5.1 Liters
If it is assumed that there are only two isotopes then the percent abundance needs to add up to 100%
100-35= 65%
The second isotope will have a 65% abundance.
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Answer:
You need to dilute 8 M HCl to 0.35 M to make 457 mL.
Explanation:
Use the equation M₁V₁=M₂V₂
Convert the mL to L : 20 mL= 0.02 L
8 M x 0.02 L = 0.35 M x V₂
V₂ = 0.4571429 L = 457 mL
Mouthwash:
solvent - water
solute - alcohols
vinegar:
solvent - water
solute - acetic acid
bleach:
solvent - water
solute - sodium hypochlorite
hope this helps!!
N=m(g)/m.wt
n=85/12(1)+16(2) =1.93 moles
