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svetlana [45]
3 years ago
7

Which molecule will undergo only London dispersion forces when interacting with other molecules of the same kind? a.HCl b.C2H5OH

c.NH3 d.CH4
Chemistry
1 answer:
ohaa [14]3 years ago
5 0

Answer:

CH4

Explanation:

London dispersion forces are a type of force acting between atoms and molecules that are normally electrically symmetric; that is, the electrons are symmetrically distributed with respect to the nucleus. They are part of the van der Waals forces(Wikipedia).  It is a temporary attractive force that results when the electrons in two adjacent atoms occupy positions that make the atoms form temporary dipoles. This force is sometimes called an induced dipole-induced dipole attraction(Chem Purdue).

If we consider HCl, C2H5OH  and NH3, we will discover that they all have polar bonds. Consequently, dipole - dipole interaction as well as hydrogen bonds exist between their molecules.

CH4 is nonpolar. Being a nonpolar molecule, the only possible intermolecular interaction forces between its molecules is the London dispersion forces.

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How does Earth's rotation affect ocean currents?
Tom [10]

Answer:

Our planet's rotation produces a force on all bodies moving relative to theEarth. ... The force, called the "Coriolis effect," causes the direction of winds and ocean currents to be deflected.

Explanation:

4 0
3 years ago
Calculate Delta G for each reaction using Delta Gf values: answer kJ ...thank you
Leni [432]

Answer:

a) \Delta G=2.6kJ

b) \Delta G=-979.57kJ

c) \Delta G=264.21kJ

Explanation:

Hello,

In this case, in each reaction we must subtract the Gibbs free energy of formation the reactants to the Gibbs free energy of formation of the products considering each species stoichiometric coefficients. In such a way, the Gibbs free energy of formations are:

\Delta _fG_{H_2}=\Delta _fG_{I_2}=0kJ/mol\\\Delta _fG_{HI}=1.3kJ/mol\\\Delta _fG_{CO_2}=-394.4kJ/mol\\\Delta _fG_{CO}=-137.3 kJ/mol\\\Delta _fG_{NH_3}=16.7 kJ/mol\\\Delta _fG_{HCl}=-95.3kJ/mol\\\Delta _fG_{MnO_2}=465.37kJ/mol\\\Delta _fG_{Mn}=0kJ/mol\\\Delta _fG_{NH_4Cl}=-342.81kJ/mol

So we proceed as follows:

a)

\Delta G=2\Delta _fG_{HI}-\Delta _fG_{H_2}-\Delta _fG_{I_2}\\\\\Delta G=2*1.3\\\\\Delta G=2.6kJ

b)

\Delta G=\Delta _fG_{Mn}+2*\Delta _fG_{CO_2}-\Delta _fG_{MnO_2}-2*\Delta _fG_{CO}\\\\\Delta G=0+2*-394.4-465.37-2*-137.3\\\\\Delta G=-979.57kJ

c)

\Delta G=\Delta _fG_{NH_3}+\Delta _fG_{HCl}-\Delta _fG_{NH_4Cl}\\\\\Delta G=16.7-95.3-(-342.81)\\\\\Delta G=264.21kJ

Regards.

6 0
3 years ago
Ammonia is produced from the reaction of nitrogen and hydrogen according to the following balanced equation: N2 1 g 2 1 3H2 1 g
bekas [8.4K]

Answer:

Mass of NH3 produced = 1217 g or 1.217*10^3 g

Explanation:

<u>Given:</u>

Mass of N2 = 1.003*10^3 g

Mass of H2 = 5.003*10^2 g

<u>To determine:</u>

Maximum mass of NH3 that can be produced when the given amounts of N2 and H2 combine

<u>Calculation:</u>

The chemical reaction corresponding to the production of ammonia is:

N2(g)+3H2(g)\rightarrow 2NH3(g)

Based on the reaction stoichiometry:

1 mole of N2 combines with 3 moles of H2 to form 2 moles of NH3

moles\ of\ N2 = \frac{Mass\ N2}{Molar\ mass N2} = \frac{1.003*10^{3}g }{28g/mol} =35.8\ moles

moles\ of\ H2 = \frac{Mass\ H2}{Molar\ mass H2} = \frac{5.003*10^{2}g }{2g/mol} =250\ moles

Since the moles of N2 is less than that of H2, the limiting reagent will be N2 which would in turn determine the amount of NH3 formed.

Based on the reaction stoichiometry the N2 : NH3 ratio = 1:2

Therefore,

moles\ of\ NH3\ produced = 2*35.8 = 71.6\ moles\\\\Mass\ of\ NH3\ produced = moles*molar mass = 71.6\ moles*17\ g/mol = 1217 g

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What is the pressure exerted by 0.500 mold sample of nitrogen in a 10.0 L container at 20 degrees Celsius
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I feel like I know this but I just can't answer it, sorry
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4 years ago
The root word sphere means
tino4ka555 [31]

Answer:

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5 0
2 years ago
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