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Mice21 [21]
2 years ago
9

Question 25 pts

Chemistry
2 answers:
Mama L [17]2 years ago
6 0
The answer is a. Hope this helped!
777dan777 [17]2 years ago
4 0
The answer is a, because the population number has increased.
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URGENT!!! What is the balanced form of this equation?
Ostrovityanka [42]

Explanation: This is a reaction of oxidation of H_2O_2 in the presence of acidified KMnO_4. Acidified KMnO_4 is a strong oxidizing agent.

To balance out the H^+ on the reactant side, we write H_2O on the product side.

Balancing out the following reaction gives us:

2MnO_4^-+6H^++5H_2O_2\rightarrow 2Mn^{2+}+8H_2O+5O_2

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3 years ago
Transpiration is the process by which ____.<br>​
saul85 [17]

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Plants add water to the atmosphere

Explanation:

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Write the balanced chemical equation between H2SO4H2SO4 and KOHKOH in aqueous solution. This is called a neutralization reaction
const2013 [10]

Answer:

0.185M sulfuric acid

Explanation:

Based on the reaction:

H₂SO₄ + 2KOH → K₂SO₄ + 2H₂O

<em>1 mole of sulfuric acid reacts with 2 moles of KOH</em>

Initial moles of H₂SO₄ and KOH are:

H₂SO₄: 0.750L ₓ (0.470mol / L) = <em>0.3525 moles of H₂SO₄</em>

KOH: 0.700L ₓ (0.240mol / L) = <em>0.168 moles of KOH</em>

The moles of sulfuric acis that react with KOH are:

0.168mol KOH ₓ (1 mole H₂SO₄ / 2 moles KOH) = 0.0840 moles of sulfuric acid.

Thus, moles that remain are:

0.3525moles - 0.0840 moles = <em>0.2685 moles of sulfuric acid remains</em>

As total volume is 0.700L + 0.750L = 1.450L, concentration is:

0.2685mol / 1.450L = <em>0.185M sulfuric acid</em>

8 0
3 years ago
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MrRissso [65]

Answer:

12 oxygen atoms are in 4 molecules of HNO3?

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the amounts of atoms of all the component in HNO3, which are 1 atom of Hydrogen, 1 atom of Nitrogen and 3 atoms of Oxygen.

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3 years ago
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A sample of 35.1 g of methane gas has a volume of 5.20 l at a pressure of 2.70 atm. calculate the temperature of the gas.
melisa1 [442]
We can use the ideal gas equation to determine the temperature with the given conditions of mass of the gas, volume, and pressure. The equation is expressed
PV=nRT where n is the number of moles equal to mass / molar mass of gas. Substituting the given conditions with R = 0.0521 L atm/mol K we can find the temperature
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