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iVinArrow [24]
2 years ago
7

Given the balanced equation: 2KClO₃ ---> 2KCl + 3O₂ How many moles of O₂ are produced when 4.0 moles of KCl are produced?

Chemistry
1 answer:
Verizon [17]2 years ago
6 0

Answer:

The answer to your question is 6.0 moles of O₂

Explanation:

Data

                      2KClO₃    ⇒     2KCl    +    3O₂

moles of O₂ = ?

moles of KCl = 4

Process

To find the number of moles of O₂, use proportions and cross multiplication.

Use the coefficients of the balanced equation.

                    2 moles of KCl ----------------- 3 moles of O₂

                    4 moles of KCl -----------------  x

                          x = (4 x 3) / 2

-Simplification

                          x = 12/2

-Result

                        x = 6 moles of O₂

-Conclusion

When 4,0 moles of KCl are produced, 6.0 moles of O₂ will be produced.                          

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Explanation:

Hello!

In this case, since the chemical reaction between copper and nitric acid is:

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By starting with 0.80 g of copper metal (molar mass = 63.54 g/mol) and considering the 1:1 mole ratio between copper and copper (II) nitrate (molar mass = 187.56 g/mol) we can compute that mass via stoichiometry as shown below:

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However, the real reaction between copper and nitric acid releases nitrogen oxide, yet it does not modify the calculations since the 1:1 mole ratio is still there:

4HNO_3+Cu\rightarrow Cu(NO_3)_2+2H_2O+2NO_2

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