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iVinArrow [24]
3 years ago
7

Given the balanced equation: 2KClO₃ ---> 2KCl + 3O₂ How many moles of O₂ are produced when 4.0 moles of KCl are produced?

Chemistry
1 answer:
Verizon [17]3 years ago
6 0

Answer:

The answer to your question is 6.0 moles of O₂

Explanation:

Data

                      2KClO₃    ⇒     2KCl    +    3O₂

moles of O₂ = ?

moles of KCl = 4

Process

To find the number of moles of O₂, use proportions and cross multiplication.

Use the coefficients of the balanced equation.

                    2 moles of KCl ----------------- 3 moles of O₂

                    4 moles of KCl -----------------  x

                          x = (4 x 3) / 2

-Simplification

                          x = 12/2

-Result

                        x = 6 moles of O₂

-Conclusion

When 4,0 moles of KCl are produced, 6.0 moles of O₂ will be produced.                          

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The radon-222 sample has a half-life of 3.8 days, and we are asked how many times would the mass divide in half after 23 days. First we calculate the amount of times division occurs by taking the number of days and dividing that by the number of days for one half-life to occur: 23/3.8 = 6.05.

We have 198.6 grams of sample, and we are going to divide it in half 6 times to determine how much of it remains after 23 days:
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